Answer:
$14000
Step-by-step explanation:
Given parameters:
Amount earned by employee x = $5250
Time duration = 3weeks
Unknown:
Amount earned in 8 weeks = ?
Solution:
Let us first find the rate of employee x earning;
Rate =
Insert parameters;
Rate =
= $1750/week
So,
In 8 weeks;
Amount earned = rate x time duration
Amount earned = $1750/week x 8weeks
Amount earned = $14000
Answer:
D
Step-by-step explanation:
If y = log x is the basic function, let's see the transformation rule(s):
Then,
1. y = log (x-a) is the original shifted a units to the right.
2. y = log x + b is the original shifted b units up
Hence, from the equation, we can say that this graph is:
** 2 units shifted right (with respect to original), and
** 10 units shifted up (with respect to original)
<u><em>only, left or right shift affects vertical asymptotes.</em></u>
Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.
Answer choice D is right.
Answer:
Here is how you do it step by step.
Step-by-step explanation:
Step 1: Simplify each side, if needed.
Step 2: Use Add./Sub. Properties to move the variable term to one side and all other terms to the other side.
Step 3: Use Mult./Divide
Step 4: Check your answer.
I find this is the quickest and easiest way to approach linear equations.
Example 6: Solve for the variable.
<u>Hope this helps!</u>
Answer:
The best way of writing this answer in an inequality pattern is 50 ≤ x ≥ 70
Step-by-step explanation:
The variable "x" is said to be greater than or equal to 50, that means that x could be 50, 51, 52, 53, 54......to infinity, all these values are true for x.
The second solution said x is greater or equal to 70. This also means that x could be 70, 71, 72, 73, ......... to infinity.
The inference that can be drawn from here is that x actually started from 50, so anything lesser than 50 is lesser than x, so 50 ≤ x. We can join the two answers together to get a range in a form like: 50 ≤ x ≥ 70
2x + 4y + 2 = 3y + 5
2x + 4y - 3y + 2 - 5 = 0
2x + y - 3 = 0