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3 years ago

Please answer the photo.

Mathematics

1 answer:

bezimeni [28]3 years ago

7 0

Answer:

the answer i think is C. AB

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Name the property of real numbers illustrated by the equation.

Ivanshal [37]

Alright, let's go through what these mean
- A is saying that you can group numbers in parenthesis differently for multiplication. Since this does not involve multiplication, this is not applicable.
- B is saying that you can expand numbers in parenthesis by multiplying it out.Since this does not involve multiplication, this is not applicable.
- C is saying that numbers multiplied by each other can be switched. Since this does not involve multiplication, this is not applicable.
- D is saying that you can group numbers in parenthesis differently for addition . Since this involves grouping numbers differently in parenthesis, this is correct!

5 0

3 years ago

Which of the filling linear relationships has a gradient of 5?

alexandr402 [8]

Answer:

gradient of five means slope of five...

that is "D" (y=5x)

Step-by-step explanation:

8 0

3 years ago

Using Euler's formula, how many

Sonja [21]

Answer:

F+V=E+2

F=6

V=8

E=?

PUT THEIR VALUE

6+8=E+2

= 14=E+2

=14-2=E

=12=E

VALUE OF E IS 12

7 0

2 years ago

HELP ME please!!!!!!!

Aleks04 [339]

Answer:

$n=20\ units$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio o its corresponding sides is proportional, and this ratio is called the scale factor

In this problem the corresponding sides are

12 units and 15 units

16 units and n units

therefore

$\frac{12}{15}=\frac{16}{n}$

Solve for n

$n=\frac{15*16}{12}$

$n=20\ units$

7 0

4 years ago

A car straight line depreciates monthly over time. After 8 months the car is worth $29,520. After 18 months the car is worth $26

HACTEHA [7]

Given :

A car straight line depreciates monthly over time.

After 8 months the car is worth $29,520 and after 18 months the car is worth $26,420.

To Find :

How much does this car depreciate each month.

Solution :

Let, depreciation of car each month is D.

$\text{Depreciation }=\dfrac{\text{Difference in prize}}{\text{Number of months}}$

$D = \dfrac{29520-26420}{18-8}\\\\D = \dfrac{3100}{10}\\\\D = \$310$

Therefore, depreciation of car each month is $310 .

Hence, this is the required solution.

5 0

3 years ago