Two numbers that gives twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90 are -10 and 4
Given :
Twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90.
Let a and b be the two unknown numbers
Lets frame equation using the given statements
Twice the sum of a number and 3 times a second number is 4.

the difference of ten times the second number and five times the first is 90

Now use these two equations to solve a and b

Add both the equations

Now find out 'a'

The two numbers are -10 and 4
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Answer:
11.49
Step-by-step explanation:
If A=8
And C=14 then
The answer is 2.686, and i am writing these extra characters to pass the 20 character qualifications.
Answer:
H0:p1=p2; Ha:p1≠p2, which is a two-tailed test.
Step-by-step explanation:
We formulate our hypotheses as
H0:p1=p2; Ha:p1≠p2, which is a two-tailed test.
Supposing the probability or proportion of the first survey is equal to the probability or proportion of the second survey. This will be the null hypothesis and the alternative hypotheses would be that these two proportions or probabilities are unequal.
This is a two tailed test.