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bija089 [108]
3 years ago
8

The area of a rectangle is 256.5m.  If the length is 18m what is the perimeter of the rectangle?

Mathematics
2 answers:
Len [333]3 years ago
7 0
Area = l x b

thus, 256.5 = 18 x b

thus b = 256.5/18
= 14.25

thus, breadth is 14.25 meters

Now perimeter = 2l + 2b

= 36 + 28.5

= 64.5

Thus, perimeter of the rectangle is 64.5 meters
irga5000 [103]3 years ago
5 0
The area of a rectangle equals length times height. (A=LH)

A=256.5 L=18

Plugging in the numbers into the equation, you get 256.5=18H. (like I substituted the numbers in)

next if you divided both sides by 18, it will cancel out the 18 in the 18H side of the equation.

So, it is 256.5/18 equaling H

256.5 divided by 18 is... 14.25

That means the height is 14.25 an the length is 18.

the perimeter is all of the sides added together. in a rectangle, the sides opposite each other are the same.

So you have two sides that are 14.25 and two that are 18 meters long.

14.25+14.25+18+18 equals the perimeter then.

So the answer would be... 64.5!
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Answer:

m∠N = 51°

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Step-by-step explanation:

It is given that ΔMNO is an isosceles triangle with base NM.

m∠N = (4x + 7)° and m∠M = (2x + 29)°

By the property of an isosceles triangle,

Two legs of an isosceles triangle are equal in measure.

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And angles opposite to these equal sides measure the same.

m∠N = m∠M

(4x + 7) = (2x + 29)

4x - 2x = 29 - 7

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m∠N = (4x + 7)° = 51°

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m∠O = 180° - (m∠N + m∠M)

         = 180° - (51° + 31°)

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