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3 years ago

The area of a rectangle is 256.5m. If the length is 18m what is the perimeter of the rectangle?

2 answers:

7 0

Area = l x b

thus, 256.5 = 18 x b

thus b = 256.5/18
= 14.25

thus, breadth is 14.25 meters

Now perimeter = 2l + 2b

= 36 + 28.5

= 64.5

Thus, perimeter of the rectangle is 64.5 meters

irga5000 [103]3 years ago

5 0

The area of a rectangle equals length times height. (A=LH)

A=256.5 L=18

Plugging in the numbers into the equation, you get 256.5=18H. (like I substituted the numbers in)

next if you divided both sides by 18, it will cancel out the 18 in the 18H side of the equation.

So, it is 256.5/18 equaling H

256.5 divided by 18 is... 14.25

That means the height is 14.25 an the length is 18.

the perimeter is all of the sides added together. in a rectangle, the sides opposite each other are the same.

So you have two sides that are 14.25 and two that are 18 meters long.

14.25+14.25+18+18 equals the perimeter then.

So the answer would be... 64.5!

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Hank the handy man charges a flat fee of $75 per visit, plus $45 per hour or fracrion of an hour

Taya2010 [7]

<h3> - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - </h3>

➷ Hank charges $75 for a visit plus $45 per hour.

Therefore, for an hour, Hank would charge $120 as 75 + 45 = 120

Mr Fixit:

As it is for one hour, we look at the first function because the time is 'less than or equal to an hour'.

Mr Fixit would charge $95 for an hour.

Therefore, Hank charges $25 more than Mr Fixit.

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4 0

3 years ago

Read 2 more answers

Factor 5a^2-30a+45, and 2x^5+x^4-2x-1.

Mrrafil [7]

Step-by-step explanation:

${5a}^{2} - 30a + 45$

$5( {a}^{2} - 6a + 9)$

5(a-3)(a-3)

5(a-3)^2

${2x}^{5} + {x}^{4} - 2x - 1$

X^4(2x+1) - (2x+1)

(x^4-1)(2x+1)

(x^2-1)(x^2+1)(2x+1)

(x-1)(x-1)(x^2+1)(2x+1)

6 0

2 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

To $28.35 find the. total cost if the tax is 6.25% and a 20% tip

Alik [6]

Your answer:
20% of 28.35 is 5.67. 6.25% of 28.35 is 1.77. Add 28.35, 5.60, and 1.77 to get the final total of $35.79

4 0

3 years ago

Read 2 more answers

Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.

AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= $\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

x₂ = $\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

If the discriminant is zero, the equation will have only one solution and it will be real
If the discriminant is greater than zero, then the equation will have two solutions and they both will be real.
If the discriminant is less than zero, then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: $b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104$

Therefore our discriminant is less than zero and we know that our equation will have two solutions in the complex numbers.

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = $\frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂= $\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

These are our two solutions in the imaginary numbers.

7 0

3 years ago