Answer:
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.
Step-by-step explanation:
given that Ty and Gajge are football players.
Carries is 15 for both and average is the same 4 for both.
But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.
Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)
But for Gajge, highest is 19 and lowest is 2.
i.e. range = 19-2 =17 very much higher than that of Ty
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.
Hi!
To solve this, we must make an equation in y = mx + b form, where m is the slope and b is the y-intercept.
Since we are looking at a graph with points, it saves us a TON of work, and all we have to do is simply look at the graph. We only need to find m and b, that's it!
M is the slope, and the slope can be represented by the change between points on a line, also known as <em>rise/run. </em>
If we start at point (-4, -1), and go to point (-2, 0), we can see that it goes up 1 and right 2, which would be represented as 1/2.
B is the y-intercept, and that is simply the point that is on the y-axis, which is the point (0, 1), so our number would be 1.
Therefore, plugging these numbers into the equation, our equation is y = <em>1/2</em>x + <em>1</em>
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Hope this helps! :D
Factor f(t) and you can identify the values of t for which the height is zero.
.. f(t) = -16t(t -3)
The projectile lands after 3 seconds in the air. (selection A)
Answer:
19
Step-by-step explanation:
1-(-18)
=1+18
=19
