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Norma-Jean [14]
4 years ago
14

Find the value of the expression -1/3-(-5/12).

Mathematics
1 answer:
IRINA_888 [86]4 years ago
6 0

Answer:

1/12

Step-by-step explanation:

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Solution :

Given :

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Let x = independent variable

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If Q(x) \neq 0

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The general solution  = complementary solution + particular integral

If Q(x) = 0

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2y''' + 15y'' + 24y' + 11y= 0

$(2D^3+15D^2+24D+11)y=0$

Auxiliary equation,

$2m^3+15m^2+24m +11 = 0$

-1  | 2    15    24     11

   <u> | 0   -2    - 13    -11  </u>

      2    13    11       0

∴ 2m^2+13m+11=0

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$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$

$=\frac{-13\pm9}{4}$

$=-5.5, -1$

So, m_1, m_2, m_3 = -1, -1, -5.5

Then the general solution is :

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3 years ago
Polygon F has an area of 36 square units. Aimar drew a scaled version of Polygon F and labeled it Polygon G. Polygon G has an ar
mariarad [96]

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3 years ago
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A candy manufacturer has 130 pounds of chocolate-covered cherries and 170 pounds of chocolate-covered mints in stock. He decides
Ilia_Sergeevich [38]

Answer:

He should prepare 260 pounds of first mixture and 0 pounds of second mixture

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That is, in first mixture,

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That is, in second mixture,

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According to the question,

The manufacturer has 130 pounds of chocolate-covered cherries and 170 pounds of chocolate-covered mints in stock,

That is,

\frac{x}{2}+\frac{y}{3} \leq 130

\frac{x}{2}+\frac{2y}{3}\leq 170

Also, pounds can not be negative,

x ≥ 0, y ≥ 0,

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By plotting the above inequalities,

Vertex of feasible regions are,

(0,255), (180, 120) and (260, 0),

Also, at (260, 0), Z is maximum,

Hence, he should prepare 260 pounds of first mixture and 0 pounds of second mixture in order to maximize his sales revenue.

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3 years ago
In physics, if a moving object has a starting position at s 0, an initial velocity of v 0, and a constant acceleration a, then t
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Actually the position function with respect to time under constant acceleration is:

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3 years ago
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Answer:

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2 years ago
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