"> + 2xy +

when x = -2 and y = -3
1 answer:
Answer:
25
Step-by-step explanation:
x² + 2xy + y²
<h3><u>i</u><u>)</u><u> </u><u>subs</u><u>titute</u><u> x</u><u> </u><u>=</u><u> </u><u>-</u><u>2</u><u> into</u><u> the</u><u> </u><u>express</u><u>ion</u></h3>
(-2)² + 2(-2)y + y²
= 4 - 4y + y²
<h3><u>ii</u><u>)</u><u> </u><u>subs</u><u>titute</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>into</u><u> </u><u>the</u><u> </u><u>expre</u><u>ssion</u></h3>
4 - 4y + y²
= 4 - 4(-3) + (-3)²
= 4 + 12 + 9
<h3><u>iii</u><u>)</u><u> </u><u>add </u><u>the</u><u> </u><u>numbers</u></h3>
4 + 12 + 9
= 16 + 9
= 25
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