Answer:
The experiment design used in this case is the between-subjected design.
Step-by-step explanation:
Between-subject design is a sort of experimental design where the individuals of an experiment are allocated to varied situations, with each individual being treated with only one of the experimental conditions.
In this case three similar ecosystems are designed containing a variety of insects and plants. Then each ecosystem to be exposed to rock music, country music, or a conventional city soundscape for two consecutive weeks.
Then after two weeks period they measured how successful the species were in each ecosystem.
The experiment design used in this case is the between-subjected design.
7x+1y = 17.00 can be simplified to y = -7x +17
<span>-7x +17 can then be substituted for y in 3x+ 4y =17.50
</span>3x+4(y) = 17.50
3x+ 4(-7x +17) = 17.50
From here you can solve for X
<span>3x + 4(-7x +17) = 17.50
</span>3x -28x + 68 = 17.50
-25x + 68 = 17.50
-68 -68
-25x = -50.50
÷-25 ÷-25
X = 2.02
You can then replace x with 2.02 in the original 7x + 1y = 17.00 to solve for y.
7(x) + 1y = 17.00
7(2.02) + y = 17.00
14.14 + y = 17.00
-14.14 -14.14
y = 2.86
Then substitute 2.02 for x and 2.86 for y in the original 3x+ 4y = 17.50 to check.
3(x) + 4(y) = 17.50
3(2.02) + 4(2.86) = 17.50
6.06 + 11.44 = 17.50
17.50 = 17.50
So
X = 2.02
and
Y = 2.86
or the solution set is (2.02, 2.86)
Hope this helps
The new area would be 270
Answer:
x=6.18
Step-by-step explanation:
<h2>
Explanation:</h2><h3>Part A.</h3>
The boundary lines of both inequalities will be dashed, because neither includes the "or equal to" case.
The first inequality solution area is bounded by a line with slope +5 and y-intercept +5. The solution area is above the line (y is greater than ...). Since the line rises steeply, the solution area looks to be to the left of the line. (It is shaded red on the attached graph.)
The second inequality solution area is bounded by a line with slope -1/2 and y-intercept +1. The solution area for this inequality is also above the line.
The solution area is where the two solution spaces overlap, in the quadrant to the upper left of the point where the lines intersect.
___
<h3>Part B.</h3>
The graph shows the point (-2, 5) to be in the solution space.
We can show this point satisfies both inequalities.
- 5 > 5(-2)+5 ⇒ 5 > -5 . . . true
- 5 > (-1/2)(-2) +1 ⇒ 5 > 2 . . . true
