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SashulF [63]
3 years ago
14

Hello i need help on all 3 of these if you could

Mathematics
1 answer:
adell [148]3 years ago
4 0

Answer:oh okay

Step-by-step explanation:

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The height of a parallelogram is 4 times the base. The base measures 3 1/2 ft find the area off the parallelogram
PilotLPTM [1.2K]

Answer:

Area = 49 ft²

Step-by-step explanation:

The formula for area of a parallelogram is A = bh, where b is the base, and h is the height.  Here, the base is given and the height is 4 times the length of the base

Here b = 3 1/2, and h = 4(3 1/2) = 14      

             3 1/2 becomes 7/2 as an improper fraction,  4(7/2) = 28/2 = 14

So the area is

A = 14(3 1/2)

A = 14(7/2)

A = 98/2

A = 49 ft²

4 0
3 years ago
Please help ASAP I don’t get this
irina1246 [14]

Answer:

Okay so 5th power of 2 Plus second power of 2 minus 3rd power of 3

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=2a%20%7B%20%7D%5E%7B2%7D%20b%20%7B%7D%5E%7B2%7D%20-%207ab%20-%2030" id="TexFormula1" title="2a
yarga [219]

Answer:

(ab - 6)(2ab + 5)

Step-by-step explanation:

Assuming you require the expression factorised.

2a²b² - 7ab - 30

Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term

product = 2 × - 30 = - 60 and sum = - 7

The factors are - 12 and + 5

Use these factors to split the ab- term

= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )

= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term

= (ab - 6)(2ab + 5) ← in factored form

5 0
3 years ago
Who is correct science or religious​
kati45 [8]

Answer:

it depends on what you believe, butttt i would say science

3 0
3 years ago
Read 2 more answers
Solve the triangle. A = 54°, b = 11, c = 8
Delicious77 [7]
In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.

For finding side a, you can answer this easily by the Law of Cosines. The equation is

a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9 

Then, we use the Law of Sines to find angles B and C. The formula would be

a/sinA = b/sinB = c/sinC
9/sin54° =  11/sinB
B = 80.4°

9/sin54° = 8/sinC
C = 45.6°

The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
5 0
3 years ago
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