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3 years ago

What is the area of a regular pentagon with a side of 7.2 and an apothem of 7

1 answer:

5 0

The area of a regular polygon is given by the formula which is expressed as:

area = (½)(apothem)(perimeter)

We calculate as follows:

area = (½)(7)(7.2 x 5)
area = 126 square units

Hope this answers the question.

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Solve the following for the indicated variable: P = a + b + c for b

podryga [215]

P = a + b + c

P - a - c = b

Answer: b = P - a - c

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3 years ago

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How long is the coastline of canada

netineya [11]

All you need to do is add 12383 and 113211 to get 125594

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2 years ago

What is the slope of the line containing (-2,5) and (4, -4)?

Musya8 [376]

Answer: slope is -3/2

Step-by-step explanation:

(-2,5) (4,-4)

Use the slope formula y2-y1/x2-x1

5-(-4)/-2-4 = -3/2

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2 years ago

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A line includes the points (4, 8) and (3, 5). What is its equation in slope-intercept form? Write your answer using integers, pr

stich3 [128]

Answer:

A line includes the points (4, 8) and (3, 5) whose equation in slope-intercept form will be :

$y=3x-4$

Step-by-step explanation:

The point slope form: $(x_1,y_1) and(x_2,y_2)$

$(y-y_1)=m(x-x_1)$

where : m = Slope of the line

$m=\frac{y_2-y_1}{x_2-x_1}$

A line includes the points (4, 8) and (3, 5).The equation of the line will be:

$m=\frac{5-8}{3-4}=3$

$(y-8)=3\times (x-4)$

$y-8=3x-12$

$y=3x-4$

(y=mx+c), where c is intercept at y axis.

The above equation represents slope-intercept form of the line.

6 0

2 years ago

Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di

quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0

3 years ago