What is the value of x? (3x) (x + 40) 20 35 60 70

Mathematics

1 answer:

Lesechka [4]3 years ago

5 0

Answer: 3x^2 +120x

Good luck !

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Algebraic fractions<br> x² + 5x+4 /<br> x²+ 4x + 3

Tresset [83]

Answer:

$\frac{x+4}{x+3}$

Step-by-step explanation:

Given

$\frac{x^2+5x + 4}{x^2+4x+3}$ ← factor numerator and denominator

= $\frac{(x+1)(x+4)}{(x+1)(x+3)}$ ← cancel common factor (x + 1) on numerator/ denominator

= $\frac{x+4}{x+3}$

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3 years ago

0.00456 scientific notation

taurus [48]

Answer:

4.56 × 10^ − 3

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10 . If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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3 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$