HELP ME I'M DOING A TEST
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The vertices of a square are its endpoints
The coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)
The given parameters are:
Calculate the distance EF
So, we have:
Add 5 to the y-coordinates of E and F
Subtract 5 to the y-coordinates of E and F
Hence, the coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)
There is no third pair
Read more about vertices at:
In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians