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Alexandra [31]
3 years ago
10

HELP ME I'M DOING A TEST

Mathematics
1 answer:
andrew-mc [135]3 years ago
8 0

Answer:

<h2><em><u>4</u></em><em><u>5</u></em><em><u> </u></em><em><u>songs </u></em><em><u>is </u></em><em><u>your</u></em><em><u> answer</u></em></h2>

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Help with question 4 please
Juliette [100K]

Answer:     y=5                           x=11

abc=def                                      

ab=de                                         <b=<e

17y-8=12+13y                              11x-4=117

-13y        -13y                                  +4   +4

4y-8=12                                      11/11x=121/11

  +8  +8                                           x=11

4/4y=20/4

y=5

7 0
3 years ago
Expand and simplify 4 ( y + 6 ) − 2 ( y − 2 )
elena-14-01-66 [18.8K]

[ Answer ]

\boxed{2y \ + \ 28}

[ Explanation ]

4(y + 6) - 2(y - 2)

[Expand] 4(y + 6): 4y + 24

4y + 24 - 2(y - 2)

[Expand] -2(y - 2): -2y + 4

4y + 24 - 2y + 4

[Simplify] 4y + 24 - 2y + 4: 2y + 28

= 2y + 28

\boxed{[ \ Eclipsed \ ]}

7 0
4 years ago
Read 2 more answers
Identify the domain and range of each relation. Use a mapping diagram to determine whether the relation a function.
Xelga [282]

Answer:

Domains- 6, 5, 1, 7

Ranges- -7, -8, 4, 5

6 0
3 years ago
Express the interval
Otrada [13]
Using inequality for the give interval which states that :
A function lies in an open interval from -2 to 6.
Hence,we can rewrite it as :

-2 < x < 6

6 0
4 years ago
Let W be the subspace of R5 spanned by the vectors w1, w2, w3, w4, w5, where
Gwar [14]
To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors. 

<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>

<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>

<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
7 0
4 years ago
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