We will use the equation x(n) = ar^(n-1) where n represents the nth term, r stands for the common ratio, and "a" stands for the first term. We use (n-1) because ar^0 is for the 1st term

Given the first term is a=2, the common ratio is r=4, then we have the equation x(n)=2*4^(n-1)

So, 128*4=512 would be the 5th term, and the 6th term would be 512*4=2048

So a6=2048

6 0

3 years ago

A = (1/2) h(b^1+b^2)

Tamiku [17]

Answer:

b^2 = 2A/h - b^1

Step-by-step explanation:

hope its right yw ;P

6 0

3 years ago

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Find the inverse of f(x)=2x+1

satela [25.4K]

Answer:

$h(x) = \frac{x-1}{2}$

Step-by-step explanation:

The inverse function is the function which when plugged in to the original one yields the argument (x).

Knowing this we do the following, let h(x) be the inverse function of f:

$f(x)=2x+1 \ \ \ \ f(h(x)) = 2(h(x)) + 1 = x\\h(x) = \frac{x-1}{2}\\Now \ we \ verify \ if \ it \ yields \ x.\\f(h(x)) = f(\frac{x-1}{2}) = 2(\frac{x-1}{2}) + 1 = x -1 + 1 = x\\Thus \ h(x) \ is \ the \ inverse\ function \ of \ f$

5 0

3 years ago

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Find the inverse laplace transform​

Find the inverse laplace transform