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erastovalidia [21]
2 years ago
5

21 less than three-fifths of a number is? I'd really like a step by step answer!

Mathematics
2 answers:
Kay [80]2 years ago
5 0

Answer:

(3x-25) over 5

Step-by-step explanation:

that's the answer

schepotkina [342]2 years ago
3 0
Hope this helps :)))
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Can any experts help me??<br> Solve for x° and y°.<br> Easy for anyone.
Annette [7]

Answer:

<u>X=46</u>

<u>Y=130</u>

<u>reflective angles</u>

Step-by-step explanation:

4 0
3 years ago
(7.8×10^7) + (9.9×10^7)
Hatshy [7]
(7.8×10⁷)+(9.9×10⁷)
(7.8×10000000)+(9.9×10000000)
(78000000)+(99000000)
177000000
8 0
2 years ago
There are 870 boys and 800 girls in a school
alina1380 [7]

Answer:

1060

Step-by-step explanation:

Given:

No. of boys = 870

No. of girls = 800

Probability that a boy chosen studies Spanish = \dfrac{2}{3}

Probability that a girl chosen studies Spanish = \dfrac{3}{5}

the number of boys in the school who study Spanish :

\dfrac{2}{3}\times 870=290\times 2=580

the number of girls in the school who study Spanish :

\dfrac{3}{5}\times 800 \\=3\times 160\\\\=480

Therefore, total number of students who study Spanish would be :

480+580=1060

8 0
3 years ago
The frequency table shows the ages of the actors
Oksanka [162]

The percentage of youth that are category 10 to 12 is the quotient of  their frequency to the total frequency

55% of the actors are 10 to 12 years old

<h3>How to determine the percentage?</h3>

From the complete question, we have the following parameters

  • Age 10 - 12 = 22 youths
  • Total youth = 40

The percentage of youth in the age category 10 - 12 is then calculated as:

Percentage = Frequency of age category 10 - 12/Total frequency

This gives

Percentage = 22/40

Evaluate the quotient

Percentage = 55%

Hence, 55% of the actors are 10 to 12 years old

Read more about frequency tables at:

brainly.com/question/16148316

3 0
2 years ago
1. forty thousand, two hundred sixteen in number form ?
kiruha [24]

Answer:

4,0216 Not sure abt the answer im trying my best sorry

3 0
2 years ago
Read 2 more answers
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