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Tju [1.3M]
3 years ago
7

Parents do your home work Me:

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0
Same—————————————————-

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What is the answer to 2y(4y)=8...
gavmur [86]
1.
Multiply 2y by 4y because they are similar
8y=8
8/8=1
4 0
3 years ago
Find the length to the nearest centimeter of the diagonal of a square 30 cm. on a side
tiny-mole [99]

Answer:

42 cm.

Step-by-step explanation:

Please find the attachment.

Let x be the length of diagonal of the square.

We have been given that length of each side of a square is 30 cm. We are asked to find the length of the diagonal of square to the nearest centimeter.

We can see from our diagram that triangle AC is the diagonal of our square.

Since all the interior angles of a square are right angles or equal to 90 degrees, so we will use Pythagoras theorem to find the length of diagonal.

AC^2=AD^2+DC^2  

Upon substituting our given values in above formula we will get,

x^2=(30\text{ cm})^2+(30\text{ cm})^2

x^2=900\text{ cm}^2+900\text{ cm}^2

x^2=1800\text{ cm}^2

Let us take square root of both sides of our equation.

x=\sqrt{1800\text{ cm}^2}

x=42.4264\text{ cm}\approx 42\text{ cm}

Therefore, the length of diagonal of our given square is 42 cm.

8 0
3 years ago
Please help me, will mark!!
BabaBlast [244]

Answer:

613 meters

Step-by-step explanation:

1)

cos(50 degrees)=324/x

x*cos(50 degrees)=324

x=324/cos(50 degrees)

x=around 504.1

2)

cos(35 degrees)=324/x

x*cos(35 degrees)=324

x=324/cos(35 degrees)

x=around 395.5

now lets find the distance in between the two people:

Distance from Shively to the tower

tan(50 degrees)=x/324

x=324*tan(50 degrees)

x= around 386.1

Distance from Sparzak to the tower

tan(35 degrees)=x/324

x=324*tan(35 degrees)

x=around 226.9

total distance=386.1+226.9=613 meters

8 0
3 years ago
Solve for x: y=-3x+6
vazorg [7]
The answer is : x= -y/3+2
8 0
3 years ago
Read 2 more answers
Vx-w=2 <br> rearrange it and make x the subject
Anit [1.1K]

Answer:

vx - w = 2 \\ vx = 2 + w \\  x =  \frac{2 + w}{v}

8 0
3 years ago
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