2 years ago

Please someone help me in this question

Mathematics

1 answer:

MaRussiya [10]2 years ago

7 0

H, 5/3
hope this helps

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Please help me, I don’t know how to solve for x on this one

Brums [2.3K]

Use trigonometry to solve for x.

The tangent function is defined to be opposite side divided by the adjacent side.

tan(78) = x/10

tan(78)(10) = x

47.0463010948 = x

We now round off to two decimal places. In other words, we round off to the nearest tenths.

47.05 = x

Done!

5 0

2 years ago

2(5m^4n^-1)^3 simplify show work please

dangina [55]

Answer:

$\large\boxed{2(5m^4n^{-1})^3=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}}$

Step-by-step explanation:

$\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\-------------------\\\\2(5m^4n^{-1})^3=2(5)^3(m^4)^3(n^{-1})^3=2(125)m^{3\cdot4}n^{-1\cdot3}=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}$

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3 years ago

PLEASE HELP!!! 50 POINTS!!! BRAINLIEST FOR FASTEST!!!

IRISSAK [1]

-20- -10=-10
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6 0

2 years ago

Read 2 more answers

Harharhaehr4ut5ihkfjharharhaehr4ut5ihkfjharharhaehr4ut5ihkfjharharhaehr4ut5ihkfj

kirill115 [55]

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3 0

2 years ago

which of the following best describes 4^2/3? a. sq root of 16, b. cube root of 4, c. sq root of four, d. cube root of 16

son4ous [18]

Answer: D) cube root of 16

================================================

Explanation:

The rule we use is

$x^{m/n} = \sqrt[n]{x^m}$

In this case, x = 4, m = 2 and n = 3.

So,

$x^{m/n} = \sqrt[n]{x^m}\\\\\\4^{2/3} = \sqrt[3]{4^2}\\\\\\4^{2/3} = \sqrt[3]{16}\\\\\\$

Showing that the original expression turns into the cube root of 16.

4 0

2 years ago