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Aleks04 [339]
2 years ago
12

Find the product. 3cd^2(6cd + 14cd^2)

Mathematics
1 answer:
klasskru [66]2 years ago
5 0
3cd^2(6cd + 14cd^2)
18cd^3 + 42cd^4
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Please help me idk this
marusya05 [52]

Answer:

The answer would be 30m squared.

Step-by-step explanation:

Multiply side and base and diveide by two.

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Javier and his study group designed a word problem, equation, table, and graph that were all supposed to represent the same info
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Graph is your answer look below for proof

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HIGHEST COMMON FACTOR OF 102 AND 153 NEED HELP EXPLAIN FOR AN EXTRA 10 POINTS
Lynna [10]

Answer:

The highest common factor for both 102 and 153 is

GCF- 51

Step-by-step explanation:

51*3= 153

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6 0
3 years ago
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A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum,  we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = \frac{x^{2} }{16}

For the equilateral triangle, the length of the side =  \frac{23 - x}{3}

Area = \frac{\sqrt{3} }{4}  a^{2}  = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}

Total Area = \frac{x^{2} }{16}  + \frac{\sqrt{3} }{36} (23-x)^{2}

\frac{dA}{dx}  = \frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x)\\

\frac{d^{2}A }{dx^{2} }  = \frac{1}{8}  + \frac{\sqrt{3} }{18}  > 0, therefore it is minimum

\frac{dA}{dx}  = 0 \\\\

\frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x) = 0\\

x = 10.00m

3 0
3 years ago
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Nataliya [291]

Answer:

Mark makes more money than Stan.

Step-by-step explanation:

There are about 52 weeks in a year. If you multiply $685 by 52, it will be $36,305.

4 0
2 years ago
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