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Aleks04 [339]
3 years ago
12

Find the product. 3cd^2(6cd + 14cd^2)

Mathematics
1 answer:
klasskru [66]3 years ago
5 0
3cd^2(6cd + 14cd^2)
18cd^3 + 42cd^4
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Which graph shows the inequality ?
OLEGan [10]

Answer:

A)  The number line goes from negative 8 to positive 8. At 0, there is an open circle. The number line is shaded to the left of 0 and on the left end of the shaded line there is a left-facing arrow.

Step-by-step explanation:

Given inequality:  x < 0

open circle:  < or >

filled circle: ≤ or ≥

Therefore, for x < 0 there will be an open circle at 0.

< means less than, so the number line will be shaded to the left of 0 and there will be a left-facing arrow on the end of the shaded line.

7 0
3 years ago
Several shapes are cut out of a piece of cardboard. Two squares of length x, five rectangles of length x and width y and two cir
forsale [732]
The correct question in the attached figure

step 1 
calculate the different volumes
a) Volume of prism square base=x*x*y=x²*y
b) Volume of the cylinder=π*(z²)*y

the combined volume of the two figures=[x²*y]+[π*z²*y]

the answer is [y*x²]+[π*y*z²]

6 0
3 years ago
By what number should -5/27 be divided to get -7/20?
jarptica [38.1K]

Answer:

Step-by-step explanation:

3 0
3 years ago
Last Saturday,the MoviePlex theater sold 1,456 tickets.The theater sold 6 times as many regular price tickets as it sold discoun
Andrews [41]

Earl is incorrect

let x be the number of discount tickets sold

then the number of regular tickets sold is 6x

the total tickets sold is 1456, thus

x + 6x = 1456

7x = 1456 ( divide both sides by 7 )

x = 208

number of discount tickets sold = 208

\frac{1456}{6} ≠ 208

but \frac{1456}{7} = 208

Earl is incorrect , dividing by 7 gives the amount sold


7 0
4 years ago
Suppose that you and a friend are playing cards and you decide to make a friendly wager. The bet is that you will draw two cards
ehidna [41]

The amount of winning is more than amount of loosing. Then the amount of winning will be $3738.

<h3>How to find that a given condition can be modelled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials.

The expected value will be

E(X) = np

Suppose that you and a friend are playing cards, and you decide to make a friendly wager.

The bet is that you will draw two cards without replacement from a standard deck.

If both cards are spades, your friend will pay you $39.

Otherwise, you have to pay your friend $5.

If this same bet is made 623 times.

The maximum amount of winning will be

E(win) = np

We have

p = 0.25

n = 623

Then we have

E(win) = 0.25 × 623

E(win) = 155.75

Then the winning amount will be

WA = 155.75 × 39

WA = $6074.25

The maximum amount of loosing will be

E(loose) = np

We have

p = 0.75

n = 623

Then we have

E(loose) = 0.75 × 623

E(loose) = 467.25

Then the loosing amount will be

LA = 467.25 × 5

LA = $2336.25

Then the amount of winning will be

⇒ $ 6074.25 - $ 2336.25

⇒ $ 3738

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

3 0
2 years ago
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