n(A-B) denotes elements which are in A but not in B
n(Au B) denotes elements in A and B
n(AnB) denotes elements that are common in A and B
Now I will add one more set
n(B-A) which denotes elements in B but not in A
So, n(AuB) = n(A-B) + n( B-A) +n(AnB)
70 = 18 +n(B-A) + 25
70 = 43 + n(B-A)
n(B-A) = 70-43
n(B-A) = 27
So, n(B) = n( B-A) + n( AnB)
= 27+25
= 52
The answer to the question is 85/100
Answer:
P = 16
Step-by-step explanation:
Given
5W = 2P + 3R ← substitute W = 4 and R = - 4 into the equation
5(4) = 2P + 3(- 4), that is
20 = 2P - 12 ( add 12 to both sides )
32 = 2P ( divide both sides by 2 )
16 = P
Answer:
1F
2C
3A
4E
5D
6B
Step-by-step explanation:
Good luck!
