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sdas [7]
3 years ago
7

1/t=1/g+1/v make g the subject​

Mathematics
1 answer:
Marina86 [1]3 years ago
7 0

Answer:

  • g = vt/(v - t)

Step-by-step explanation:

<u>See the solution in steps:</u>

  • 1/t = 1/g + 1/v
  • 1/g = 1/t - 1/v
  • 1/g = (v - t)/(vt)
  • g = vt/(v - t)
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Can someone please help me.
wariber [46]
A= 3, b= 14 c= -5

To find this, use the foil method of first, outside, inside, and then last. By doing so you’ll get the answer of 3x^2 + 14x -5
4 0
3 years ago
Evaluate: |-5|-|6|+|8|​
marin [14]

Answer: 7

Step-by-step explanation:

First find the absolute value of the numbers then apply the signs.

The absolute value of -5 is 5

The absolute value of 6 is 6

The absolute value of 8 is 8

5 - 6 + 8  = 7

8 0
3 years ago
sanjay hockey team played 25 games each season they won 80% of there game. How many games did they lose
Contact [7]

Answer:

5 games

Step-by-step explanation:

Do 80% of 25 which would be 20 and then you can determine how many they lost so if they won 20 games and they have 25 games total then they lost 5 games.

3 0
3 years ago
suppose you have a job teaching swimming lessons and get paid $9 an hour. you also have a job as a cashier and get paid $7/hr. I
Maslowich

Answer:

B

Step-by-step explanation:

In A, it says that 9s +7c can be lower or equal to 160. This is wrong.

In C, it says that 9s +7c can only be higher than 160, when the question says at least, which means it can also be equal to 160, making it wrong.

In D, it says that 9s +7c can be lower or equal to 20. This is wrong.

Through elimination, only B can be right.

5 0
3 years ago
Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.
JulsSmile [24]
If \frac{3}{4} is a root of the equation, q(x) = 6x3 + 19x2 – 15x – 28 then by the factor formula q(\frac{3}{4}) = 0; if that is not the case then \frac{3}{4} cannot be a factor of the function.

Now, q(\frac{3}{4}) = 6(\frac{3}{4})³ + 19(\frac{3}{4})² – 15(\frac{3}{4}) – 28
                                               = - \frac{833}{32}

Therefore Yuri, since q(\frac{3}{4}) ≠ 0 then it implies that \frac{3}{4} is not a root of q(x).

Additionally, a root should be expressed in terms of x, thus the possible root ought to be written as x = \frac{3}{4}, instead of just \frac{3}{4}
6 0
3 years ago
Read 2 more answers
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