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Tresset [83]
2 years ago
15

Given the function defined in the table below, find the average rate of change, in simplest form, of the function over the inter

val 10< x <22
Mathematics
1 answer:
slava [35]2 years ago
8 0

Using it's concept, the average rate of change of the function over the interval 10 < x < 22 is given by:

r = \frac{f(22) - f(10)}{12}

<h3>What is the average rate of change of a function over an interval?</h3>

It is given by the change in the <u>output divided by the change in input</u>.

Over the interval 10 < x < 22, the outputs are f(10) and f(22), hence the rate of change is given by:

r = \frac{f(22) - f(10)}{12}

More can be learned about the average rate of change of a function at brainly.com/question/24313700

#SPJ1

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pychu [463]

Answer:

The answer is 7 + b ≤ 16

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3 years ago
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Mr lee's homeroom class won a pizza party withfive pizzas. The students ate 3 1/3 of the pizzas. How many pizzas are left?
algol13
A whole pizza has 3 x 1/3 pizzas.
So if you eat 3 of 5, 2 pizza lefts.
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3 0
3 years ago
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A 1178 foot cable weighs 266 pounds. How many pounds will 36 inches of cable weight? round answer to two decimal places (1 pound
Aliun [14]

Answer:

36 inches of cable weighs 0.68 lbs

Step-by-step explanation:

1178 ft cable weighs 266 lbs...and u want to know how many lbs a 36 inch cable weighs....

we need to turn ur ft to inches....1 ft = 12 inches....so 1178 ft = (1178 * 12) = 14,136 inches

14136 in. to 266 lbs = 36 in.to x lbs

14136 / 266 = 36 / x...cross multiply

14136x = (36)(266)

14136x = 9576

x = 9576 / 14136

x = 0.6774 rounds to 0.68 lbs <===

6 0
3 years ago
For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. Minitab was used
kkurt [141]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Correlation Coefficient (r) = 0.989

alph=0.05

Number of observations (n) = 8

determine if there is a linear correlation between chest size and weight.

Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.

What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?

To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.

r^2 = square of the correlation Coefficient

r^2 = 0.989^2 = 0.978121

Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.

4 0
4 years ago
2,058 in expended form
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Answer:

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Step-by-step explanation:

5 0
4 years ago
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