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Tresset [83]
2 years ago
15

Given the function defined in the table below, find the average rate of change, in simplest form, of the function over the inter

val 10< x <22
Mathematics
1 answer:
slava [35]2 years ago
8 0

Using it's concept, the average rate of change of the function over the interval 10 < x < 22 is given by:

r = \frac{f(22) - f(10)}{12}

<h3>What is the average rate of change of a function over an interval?</h3>

It is given by the change in the <u>output divided by the change in input</u>.

Over the interval 10 < x < 22, the outputs are f(10) and f(22), hence the rate of change is given by:

r = \frac{f(22) - f(10)}{12}

More can be learned about the average rate of change of a function at brainly.com/question/24313700

#SPJ1

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What is the equation of a vertical ellipse with a major axis= 20 and a minor axis = 14?​
Sunny_sXe [5.5K]

\bold{\text{Answer:  b.}\quad \dfrac{y^2}{100}+\dfrac{x^2}{49}=1}

<u>Step-by-step explanation:</u>

The ellipse is vertical so y has the biggest radius.

Major axis (y) = 20 so the y-radius is 20/2 = 10

Minor axis (x) = 14 so the x-radius is 14/2 = 7

The equation of an ellipse is:   \dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1   where

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Given: a = 7, b = 10

Assume: (h, k) = (0, 0)

\dfrac{(x-0)^2}{7^2}+\dfrac{(y-0)^2}{10^2}=1\\\\\\\dfrac{x^2}{49}+\dfrac{y^2}{100}=1\\\\\\\longrightarrow \dfrac{y^2}{100}+\dfrac{x^2}{49}=1

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1 year ago
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We must plug in what we know in order to find the value of b.
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Now we know our equation is y = 1.5x + 0.5

We can find any other point on the line by plugging in any x-value. Let's try 5.
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vampirchik [111]

Answer:

5x+2y+6=0

Step-by-step explanation:

General equations are in the form Ax + By + C = 0

So you can add 6 to both sides to make:

5x+2y+6=0

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