Answer: 
Step-by-step explanation:
Given
The yellow line leaves the station every 6 min
The red line leaves the station every 8 min
They both leave at 
Both trains meet again after, LCM(6,8)=24 min
i.e. at
<span>For the
presented problem, the solution would be</span><span> </span><span>v</span><span>(0)=0</span><span>v(0)=0</span><span> is</span><span>v</span><span>(</span><span>t</span><span>)−</span><span>mgb</span><span>=</span><span>e</span><span>−</span><span>b</span><span>/</span><span>m</span><span>⋅</span><span>t</span><span>(</span><span>v</span><span>0</span><span>−</span><span>mgb</span><span>)</span><span>⟺</span><span>v</span><span>(</span><span>t</span><span>)=</span><span>mgb</span><span>(</span><span>1−</span><span>e</span><span>−</span><span>b</span><span>/</span><span>m</span><span>⋅</span><span>t</span><span>)</span><span>≈</span><span>g</span><span>⋅</span><span>t</span><span>−</span><span>gb</span><span>2</span><span>m</span><span>⋅</span><span>t</span><span>2</span><span>,
with the following given, </span><span>
m</span><span>=180[lb]=81.6[kg]</span><span> </span>
<span>g</span><span>=9.81[m/s</span><span>2</span><span>]</span><span />
<span>b</span><span>=0.75[kg</span><span>⋅</span><span>m/s</span><span>2</span><span>⋅</span><span>s/ft]=0.2286[kg/s]</span><span />
<span>The solution that the
friction provides is </span><span>v</span><span>(</span><span>t</span><span>)=3501.7[m/s]</span><span>⋅</span><span>(</span><span>1−</span><span>e</span><span>−0.00280[1/s]</span><span>⋅</span><span>t</span><span>), where I get </span><span><span>96.69</span></span><span /><span><span><span><span>[</span></span><span /><span><span>m</span></span><span /><span><span><span><span>/</span></span></span></span></span><span><span><span>s</span></span><span /><span><span>]</span></span></span><span>=</span></span><span /><span><span>317.2</span></span><span /><span><span><span><span>[</span></span><span /><span><span>f</span><span>t</span></span><span /><span><span><span><span>/</span></span></span></span></span><span><span><span>s</span></span><span /><span><span>]</span></span></span></span><span><span /></span><span>. I
am hoping that this answer has satisfied your query about this specific
question.<span /></span>
Day = 8 4/5 ÷ 4
day = 44/5 ÷ 4
day = 44/5 × 1/4
day = 44/20
day = 11/5
day = 2 1/5
Answer:
<em>BC = 27</em>
Step-by-step explanation:
The point B is the midpoint of AC
=> AB = BC
=> 4x - 5 = 11 + 2x
Let's calculate x to work out BC
Transferring the components containing x to the left side, and other components to the right side:
=> 4x - 2x = 11 + 5
Simplifying both sides:
=> 2x = 16
=> x = 8
Working out BC:
=> BC = 11 + 2x = 11 + 2(8) = 11 + 16 = 27
Hope this helps!
Using synthetic division, you can find the quadratic factor to be
.. 2x^2 -3x +1
That, in turn, factors as
.. (2x -1)(x -1)
So the complete factorization is
.. (2x -1)(x -1)(x +3)
and the zeros are confirmed by a graphing calculator to be
.. x = 1/2, 1, -3
