498 is approximately 500
12 is approximately 10
500/10 = 50
So, 498/12 is approximately 50.
Maybe 833. I don’t know if I’m correct or not plz tell me
Answer:

Step-by-step explanation:
Given


Required
The distance between them
This is calculated as:

So, we have:




Hello,
(f-g)(x)=3x²+1-1+x=3x²+x
(f-g)(2)=3*2²+2=3*4+2=14