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disa [49]
3 years ago
6

Gia opened two savings accounts at two diffrent banks. One account earns an annual 3.4% simple interest, and the other earns hal

f as much. If she deposited $509 in each account, how much total interests will sh have earned in 3 years? A:$153.00 B:$38.25 C:$76.50 D:$51.00
Mathematics
1 answer:
dsp733 years ago
5 0

Interest from first account is :

I_1 = \dfrac{p\times r \times t}{100}\\\\I_1 = \dfrac{509\times 3.4\times 3}{100}\\\\I_1 =\$ 51.918

Interest form second account is :

I_2 = \dfrac{p\times r\times t}{100}\\\\I_2 = \dfrac{509\times 1.7\times 3}{100}\\\\I_2 =  \$25.959

So, total interest is :

I = I_1 + I_2 \\\\I = 51.918 + 25.959\\\\I = \$77.877

Therefore, total interest is $77.877 .

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Solve by elimination -2x+2y=6 and 4x×2y=-5
Valentin [98]

Answer:

x=-11/6, y=7/6. (-11/6, 7/6).

Step-by-step explanation:

-2x+2y=6

4x+2y=-5

-----------------

2(-2x+2y)=2(6)

4x+2y=-5

----------------------

-4x+4y=12

4x+2y=-5

----------------

6y=7

y=7/6

4x+2(7/6)=-5

4x+14/6=-5

4x=-5-14/6

4x=-30/6-14/6

4x=-44/6

x=(-44/6)/4

x=(-44/6)(1/4)

x=-44/24

simplify

x=-11/6

3 0
3 years ago
Please Help ASAP! Simplify roots of negative numbers. Express your answer in simplified form.
Korolek [52]

Answer:

3i\sqrt2

Step-by-step explanation:

We can rewrite the square root of negative 18 as \sqrt{18} \cdot\sqrt{-1}. We can evaluate these two quantities separately. The square root of 18 can be factored to get 3 squared times 2. We can take the 3 out to get 3\sqrt2. Now, the square root of negative one can be rewritten as i, so this is equal to 3i\sqrt2

7 0
3 years ago
The fuel economy of a car, measured in miles per gallon, is modeled by the function ƒ(s) = –0.009s2 + 0.699s + 12 where s repres
Kisachek [45]

Answer:

The maximum fuel economy of the car is 25.57225

Step-by-step explanation:

we are given

f(s)=-0.009s^2+0.699s+12

where

where s represents the average speed of the car, measured in miles per hour

So, we have to maximize f(s)

So, firstly we will find derivative

f'(s)=-0.009*2s+0.699*1+0

f'(s)=-0.018s+0.699

now, we can set it to 0

and then we can solve for s

f'(s)=-0.018s+0.699=0

s=\frac{233}{6}

To find maximum fuel economy , we can plug s into f(s)

f(\frac{233}{6})=-0.009(\frac{233}{6})^2+0.699(\frac{233}{6})+12

f(\frac{233}{6})=25.57225

So,

The maximum fuel economy of the car is 25.57225

4 0
3 years ago
Read 2 more answers
How hard is calculus compared to algebra 2?
PSYCHO15rus [73]

Answer:

It's not much harder.

Calculus just requires that you put in a lot of work doing practice problems, which is something a lot of people aren't willing to do. And, it just involves a lot of memorization of formulas.

5 0
3 years ago
What does 15cubed look like in exspanded form
Mashutka [201]
15^3 = 15\times 15\times 15=3,375\\\\\sf in~expanded~form:\\\boxed{3,000 + 300 + 70+5}
6 0
3 years ago
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