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aleksley [76]
3 years ago
11

A school sold small and large boxes of fruit for a fundraiser. One student sold 5 small boxes and 13 large boxes for $232. Anoth

er student sold 12 small boxes and 7 large boxes for $218. Their sales can be represented in two equations where x represents the price of the small boxes and y represents the price of the large boxes. Which constants can be multiplied by the equations so one variable will be eliminated when the systems are added together? Check all that apply.
The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.
The first equation can be multiplied by –7 and the second equation by 13 to eliminate y.
The first equation can be multiplied by 7 and the second equation by –13 to eliminate y.
The first equation can be multiplied by 12 and the second equation by –5 to eliminate x.
The first equation can be multiplied by 7 and the second equation by 13 to eliminate y.
Mathematics
2 answers:
user100 [1]3 years ago
6 0

Answer:

A,C,D,E

Step-by-step explanation:

algol [13]3 years ago
5 0

Answer: the right answer is

The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.

The first equation can be multiplied by –7 and the second equation by 13 to eliminate y.

The first equation can be multiplied by 7 and the second equation by –13 to eliminate y.

The first equation can be multiplied by 12 and the second equation by –5 to eliminate x.

Step-by-step explanation:

e d g e n u i t y  and it says check all that apply ,it was not (A).

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Express a decimal number ( ie 0.768) - process description please - as a rational number (96/125)?
Stels [109]

The decimal representation of any number is a linear combination of powers of 10. In other words, given a number like 123.456, we can expand it as

1\cdot10^2+2\cdot10^1+3\cdot10^0+4\cdot10^{-1}+5\cdot10^{-2}+6\cdot10^{-3}

10^{-n}=\dfrac1{10^n} for any n, so the above is the same as

100+20+3+\dfrac4{10}+\dfrac5{100}+\dfrac6{1000}=\dfrac{100000+20000+3000+400+50+6}{1000}=\dfrac{123456}{1000}

Similarly, we can write

0.768=\dfrac{768}{1000}

Now it's a question of reducing the fraction as much as possible. We have \mathrm{gcd}(768,1000)=8 so

\dfrac{768}{1000}=\dfrac{96\cdot8}{125\cdot8}=\dfrac{96}{125}

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3 years ago
Solve v^3 = -26 where v is a real number.<br> Simplify your answer as much as possible.
il63 [147K]

Answer:

nearby -3

Step-by-step explanation:

When v^3 is -26, your v is equal to -\sqrt[3]{26}.

3^3 is 27, so v is nearby 3.

or, It would be nearby 3.9

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3 years ago
If a snail moves six feet in 15 minutes, how far will it go in two hours?
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Which expression is equivalent to ( 4mn / m^-2n^6)^-2a. n^6 / 16m^8b. n^10 / 16m^6c. n^10 / 8m^8d. 4m^3 / n^8?
Eva8 [605]

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