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aleksley [76]
3 years ago
11

A school sold small and large boxes of fruit for a fundraiser. One student sold 5 small boxes and 13 large boxes for $232. Anoth

er student sold 12 small boxes and 7 large boxes for $218. Their sales can be represented in two equations where x represents the price of the small boxes and y represents the price of the large boxes. Which constants can be multiplied by the equations so one variable will be eliminated when the systems are added together? Check all that apply.
The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.
The first equation can be multiplied by –7 and the second equation by 13 to eliminate y.
The first equation can be multiplied by 7 and the second equation by –13 to eliminate y.
The first equation can be multiplied by 12 and the second equation by –5 to eliminate x.
The first equation can be multiplied by 7 and the second equation by 13 to eliminate y.
Mathematics
2 answers:
user100 [1]3 years ago
6 0

Answer:

A,C,D,E

Step-by-step explanation:

algol [13]3 years ago
5 0

Answer: the right answer is

The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.

The first equation can be multiplied by –7 and the second equation by 13 to eliminate y.

The first equation can be multiplied by 7 and the second equation by –13 to eliminate y.

The first equation can be multiplied by 12 and the second equation by –5 to eliminate x.

Step-by-step explanation:

e d g e n u i t y  and it says check all that apply ,it was not (A).

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Hence, the solution must be a < x < b.

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