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aleksley [76]
3 years ago
11

A school sold small and large boxes of fruit for a fundraiser. One student sold 5 small boxes and 13 large boxes for $232. Anoth

er student sold 12 small boxes and 7 large boxes for $218. Their sales can be represented in two equations where x represents the price of the small boxes and y represents the price of the large boxes. Which constants can be multiplied by the equations so one variable will be eliminated when the systems are added together? Check all that apply.
The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.
The first equation can be multiplied by –7 and the second equation by 13 to eliminate y.
The first equation can be multiplied by 7 and the second equation by –13 to eliminate y.
The first equation can be multiplied by 12 and the second equation by –5 to eliminate x.
The first equation can be multiplied by 7 and the second equation by 13 to eliminate y.
Mathematics
2 answers:
user100 [1]3 years ago
6 0

Answer:

A,C,D,E

Step-by-step explanation:

algol [13]3 years ago
5 0

Answer: the right answer is

The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.

The first equation can be multiplied by –7 and the second equation by 13 to eliminate y.

The first equation can be multiplied by 7 and the second equation by –13 to eliminate y.

The first equation can be multiplied by 12 and the second equation by –5 to eliminate x.

Step-by-step explanation:

e d g e n u i t y  and it says check all that apply ,it was not (A).

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Over 182 days of school each, school day last 7 hour how many hours are the students in school. thank you​
adelina 88 [10]

The students spend 1274 hours in school.

<h3>How to determine the number</h3>

From the information given, we have that:

  • There are 182 school days
  • Each school days take 7 hours

We can then say that, if takes 7 hours for each school day and there are 182 days, then the hours students spent in school is;

= 182 days × 7 hours

Multiply through

= 1274 hours

The students are in school for 1274 hours.

Hence, the students spend 1274 hours in school.

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7 0
1 year ago
If f(x)=3x^2+1 and g(x) =1-x, what is the truly value of (f-g)(2)
Lilit [14]

Answer:

14

Step-by-step explanation:

f(x)=3x²+1

f(2) = 3 x 2² + 1 = 13

g(x) =1-x

g(2) = 1 - 2 = -1

(f-g)(2) f(2) - g(2) = 13 - (-1) = 14

8 0
3 years ago
By what scale factor is the larger container increased?<br> A. 2<br> B. 2.75<br> C. 2.25<br> D. 2.5
lys-0071 [83]

Answer:

I think A, but i'm not the smartest

Step-by-step explanation:

4 0
3 years ago
Select the correct answer from each drop-down menu.
olganol [36]

The system of inequalities is:

y ≤ -0.05*x^2 + 6x

y >  1.5x + 45

(30, 90) is not a solution of that system, while (60, 160) is a solution.

<h3>How to get the system of inequalities?</h3>

We know that the revenue y is given by:

y ≤ -0.05x^2 + 6x

And we know that the costs are 1.5x + 45, and the revenue must be larger than that, so we also have the inequality:

y >  1.5x + 45

So the system is:

y ≤ -0.05*x^2 + 6x

y >  1.5x + 45

Now, the point (30, 90) means that we need to replace x by 30 and y by 90, replacing that in the second inequality, we will get:

90 > 1.5*30 + 45 = 90

90 > 90

This is false, so the point is not a solution of this inequality, meaning that the point is not a solution of the system.

For the second point we do the same: x= 60, y = 160, replacing that in the second inequality we get:

160 > 1.5*60 + 45 = 135

160 > 135

This is true, now we need to check with the other inequality.

160 ≤  -0.05*60^2 + 6*60 = 180

This is also true.

So the point (60, 160) is a solution to the system.

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8 0
2 years ago
Read 2 more answers
Factor the following expression x^2-36
Tomtit [17]
Factor the following:
x^2 - 36
x^2 - 36 = x^2 - 6^2:
x^2 - 6^2
Factor the difference of two squares. x^2 - 6^2 = (x - 6) (x + 6):
Answer:  (x - 6) (x + 6)
7 0
3 years ago
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