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marishachu [46]
3 years ago
9

Amanda goes to a football game with 2

Mathematics
2 answers:
zlopas [31]3 years ago
4 0
$99.25

25.50 x 3 = 76.50
4.75 x 2 = 9.50
76.50 + 9.50 = 86
86 = 3.50 = 89.50
89.50 + 3.00 = 92.50
2.25 x 3 = 6.75
92.50 + 6.75 = 99.25
PtichkaEL [24]3 years ago
3 0

Answer:

99.25

Step-by-step explanation:

3 times 25.50 = 76.5

2 times 4.75 =

3 times 2.25 = 6.75

3.5 + 3 + 76.5 + 9.5 + 6.75 = 99.25

In total, they spent $99.25 at the football game.

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Answer:

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Step-by-step explanation:

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Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.​
vivado [14]

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}

\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}

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2 years ago
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Answer:

Step-by-step explanation:

16.

RT=17.885

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19

∠A = 180° - B - C = 1.36944 rad =

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