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3 years ago

Amanda goes to a football game with 2

2 answers:

4 0

$99.25

25.50 x 3 = 76.50
4.75 x 2 = 9.50
76.50 + 9.50 = 86
86 = 3.50 = 89.50
89.50 + 3.00 = 92.50
2.25 x 3 = 6.75
92.50 + 6.75 = 99.25

PtichkaEL [24]3 years ago

3 0

Answer:

99.25

Step-by-step explanation:

3 times 25.50 = 76.5

2 times 4.75 =

3 times 2.25 = 6.75

3.5 + 3 + 76.5 + 9.5 + 6.75 = 99.25

In total, they spent $99.25 at the football game.

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The length of a rectangular fenced enclosure is 12 feet more than the width. If Farmer Dan has 100 feet of fencing, write an ine

EastWind [94]

Let l length, w width, p perimeter:

l=12+w

2(l+w)=p

2((12+w)+w)= 100

2(12+2w)=100

12+2w=50

2w=38

w=19

l=12+w=12+9= 21

l=21

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3 years ago

What is the value of a 6 15 -- = ------- 22 a

Naily [24]

Step-by-step explanation:

$\frac{6}{22} = \frac{15}{a}$

$\frac{3}{11} = \frac{15}{a}$

$3a = 15 \times 11$

$3a = 165$

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3 years ago

Given the equation, y=1/2x-2, determine the value for x when y=8

Olegator [25]

The answer is x= 20.
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5 0

3 years ago

Rounding 4540 and 1964 to the nearest hundred

alexandr1967 [171]

Answer:

They are all ready rounded to the nearest Hundred ??

Step-by-step explanation:

They are already

8 0

3 years ago

Read 2 more answers

In Example 3, the track has 6 lanes that are each 1 meter in width. a. What is the outer perimeter of the track? Round your answ

son4ous [18]

Answer:

Incomplete question, check attachment for the necessary diagram

Step-by-step explanation:

Note in the attachment,

We have two identical straight line of lenght

L1 = L2 = 84.39m

We also have two identical semicircle or radius 36.5m to the first track lane

But this is not the radius of the circle, the radius of the circle will now be 36.5 plus the 6 track lane and we are told that one track lane is 1m, then, the track lane is 6m

So, radius = 36.5+6

r = 42.5m

Then, we need to calculate the perimeter of the semicircle using the formula of perimeter of a circle and dividing by2

P = 2πr/2

P =πr

P = 22/7 × 42.5

P = 133.57 m

Then, the arc 1 is equal to arc 2 which is equal to 133.57 m

A1 = A2 = 133.57 m

Now we have all the dimensions,

Then, the perimeter can be calculated by adding the length of the sides

The perimeter of the field = Lenght of the two straight lines plus the length of the two semicircle arc

P = L1 + L2 + A1 + A2

P = 84.39 + 84.39 + 133.57 + 133.57

P =435.923 m

So, to the nearest meter

P ≈ 436m

The perimeter of the track is 436m

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3 years ago