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3 years ago

2x+y=3 passes from origin. is this statement true or false

Mathematics

2 answers:

WINSTONCH [101]3 years ago

8 0

Answer:

the answer is false.

Step-by-step explanation:

gayaneshka [121]3 years ago

6 0

Answer:

False

Step-by-step explanation:

2x+y=3

⇒ This equation can be written in the form of y = mx + c where m is the slope, c is the y-intercept and x and y are x and y coordinates respectively of the point where the the line passes.

2x+y=3

y = -2x + 3.

If the line passes through the origin (0,0), then c = 0. This is not the case in our eqation.

Again if the question passes through the origin, by substituting the point (0,0) in the question it would satify it.

2x+y=3 ⇒ 2(0) + 0 = 3

0 + 0 ≠ 3

0 ≠ 3

The statement is false.

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Andrews [41]

Answer:

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Step-by-step explanation:

Let's make every fraction improper first.

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2 years ago

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Answer: $x\leq 3$

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Step-by-step explanation:

1) Simplify both sides of the inequality:

$4x+8\geq 5x+5$

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4) Subtract $8$ from both sides:

$-x+8-8\geq 5-8$

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6) Divide both sides by $-1$ :

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7) Simplify:

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2 years ago

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Looks like the series is supposed to be

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The series telescopes; consider the $k$ th partial sum of the series,

$S_k=\displaystyle\sum_{n=1}^k\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}$

$S_k=\displaystyle\left(\frac3{\sqrt3}-\frac32\right)+\left(\frac32-\frac3{\sqrt5}\right)+\cdots+\left(\frac3{\sqrt{k+1}}-\frac3{\sqrt{k+2}}\right)+\left(\frac3{\sqrt{k+2}}-\frac3{\sqrt{k+3}}\right)$

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