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2 years ago

15

If two cars are 492.5 miles apart, the first car left at 1:00 at a constant rate of 55 mph and the second car left an hour later

and moving at a constant speed of 70 mph. What time will the two cars pass each other?

1 answer:

Mama L [17]2 years ago

8 0

Answer:

I don't know, need points

Step-by-step explanation:

Use keys on your computer maybe.

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How to solve for 6x-12+2x=3+8x-15

Alecsey [184]

6x−12+2x=3+8x−15

Simplify:

6x+−12+2x=3+8x+−15

(6x+2x)+(−12)=(8x)+(3+−15)(Combine Like Terms)

8x+−12=8x+−12

8x−12=8x−12

Subtract 8x from both sides.

8x−12−8x=8x−12−8x

−12=−12

Add 12 to both sides.

−12+12=−12+12

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2 years ago

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 46.046.0 and

Gala2k [10]

Answer:

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is 0.10

Step-by-step explanation:

The Uniform Distribution, also known as Rectangular Distribution, is a type of Continuous Probability Distribution. It has a continuous random variable restricted to a finite interval and its probability function has a constant density during this interval.

The formula of probability if given by:

f(x)=

$\left \{ {{\frac{1}{b-a}; \ a \leq x \leq b } \atop {0}; \ x \ otherwise } \right.$

In this exercise a= 46.0 and b= 56.0

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is:

$\int\limits^{51.25}_{50.25} {\frac{1}{56-46} } \, dx = \int\limits^{51.25}_{50.25} {\frac{1}{10} } \, dx = \frac{1}{10} \times (51.25 - 50.25)=\frac{1}{10}=0.1$

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2 years ago

Whats the value of 3x^2 + 5x when x=3 . show woro please if you can.

lubasha [3.4K]

Answer:

42

Step-by-step explanation:

3x^2 +5x

Let x=3

3(3)^2 +5(3)

3*9 +15

27+15

42

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2 years ago