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Serggg [28]
3 years ago
15

If two cars are 492.5 miles apart, the first car left at 1:00 at a constant rate of 55 mph and the second car left an hour later

and moving at a constant speed of 70 mph. What time will the two cars pass each other?
Mathematics
1 answer:
Mama L [17]3 years ago
8 0

Answer:

I don't know, need points

Step-by-step explanation:

Use keys on your computer maybe.

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How do you find the missing height of a triangle?
g100num [7]

Answer:

Use the Pythagorean theorem

Step-by-step explanation:

The pythagorean theorem is a^{2} +b^{2} =c^{2} where a is a height, b is a height, and c is the hypotenuse, which is the longest side of a triangle. For example, if the triangle has two side with lengths of three and four we would put them into the equation to get:

3^{2} +4^{2} =c^{2}

Simplify the equation to get:

9+16=c^2

Add 16 and 9 to get 25 and take the square root of both sides:

\sqrt{25} =c

The sqrt of 25 is 5. Therefore, the length of the hypotenuse, or c, is 5.

8 0
3 years ago
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Sales of $10,000 increase by 65% each year.<br> Whats the y
Elan Coil [88]

Answer:

153.8 I guess... this is your answer

3 0
3 years ago
Joe paid $14 for a board game. this is 70% of the original price. what was the original price?
tino4ka555 [31]

Step-by-step explanation:

It is given that Joe paid 14.00 for a board game this is 70% of the original price what is the original price.

Let the original price of board game be

X.

x * 70/100 = 14

x * 7/10 = 14

Multiply both sides by 10.

7x = 140

Divide both sides by 7.

x = 20

4 0
1 year ago
SEE PHOTO! If 1 measures 135°, what is the measure of 8? (Lines b and c are parallel.)
Bezzdna [24]

Answer:

Measure 8 is 135°

Step-by-step explanation:

Measure 1 and Measure 8 are alternate exterior angles.

7 0
3 years ago
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Find the oth term of the geometric sequence 5,--25, 125,
Genrish500 [490]

Given the geometric progression below

5,-25,125,\ldots

The nth term of a geometric progression is given below

T_n=ar^{n-1},\begin{cases}a=\text{first term} \\ r=\text{common ratio}\end{cases}

From the geometric progression, we can deduce the following

\begin{gathered} T_1=a=5 \\ T_2=ar=-25 \\ T_3=ar^2=125 \end{gathered}

To find the value of r, we will take ratios of two consecutive terms

\begin{gathered} \frac{T_2}{T_1}=\frac{ar}{a}=\frac{-25}{5} \\ \Rightarrow r=-5 \end{gathered}

To find the 9th term of the geometric, we will have that;

\begin{gathered} T_9=ar^8=5\times(-5)^8=5\times390625 \\ =1953125 \end{gathered}

Hence, the 9th term of the geometric progression is 1953125

8 0
1 year ago
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