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3 years ago

A mother paid $15.05 for flour at a store that sells flour for $0.86 per pound.

Mathematics

2 answers:

expeople1 [14]3 years ago

8 0

Answer:

17.5

Step-by-step explanation:

15.05 divided by 0.86 is 17.5

wariber [46]3 years ago

6 0

Answer:

the mother bought 17.5 pounds

Step-by-step explanation:

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How is the equation Y= 2X similar to the equation Y = 2X +3. how is it different

Svetlanka [38]

Answer:

2x in common (slope)

Step-by-step explanation:

similar because they both have a slope of 2

different because the 2nd equation has a y intercept of 3

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4 years ago

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Can somebody help please and thank you :)

Marizza181 [45]

I can help soo first u need to read the question and see what’s its telling u then u got to see what to did like division adding and the other stuff but u are going to divide

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3 years ago

Ryan is riding his bike. He biked a distance of 12 miles at a rate of 4 miles per hour. Rearrange the distance formula, d = rt,

alexandr402 [8]

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3 years ago

Verify the following identity: (csc theta -cot theta )/(sec theta -1) A. sec theta B. cos theta C. cot theta D. sin theta

alexdok [17]

Answer:

C. cot theta

Step-by-step explanation:

(csc theta -cot theta )/(sec theta -1)

csc = 1/ sin

cot = cos / sin

sec = 1 / cos

Let x = theta

(1/ sin x -cos x / sin x )/(1/ cos x -1)

Getting a common denominator in the denominator and combining terms

(1- cos x)/ sinx / ( 1 - cos x) / cos x

(1- cosx) (1- cosx)

----------- ÷ ------------

sinx cos x

Copy dot flip

(1- cosx) cosx

----------- * ------------

sinx 1 -cos x

Cancel like terms

cos x / sin x

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3 years ago

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$