Let x be the unknown angle.
We know that x+50=120 because the value of an exterior angle of a triangle is equal to the sum of the other 2 interior angles.
x+50 = 120
Subtract both sides by 50
x = 70
The value of the unknown angle is 70 degrees.
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Area of a square = Side × Side
Side = 7x-3
Area of the square = (7x-3) × (7x-3)
= 7x(7x-3) -3(7x-3)
= 49x^2 -21x -21x +9
=49x^2 -42x +9
Triangle area = 8 x 3/2
= 12
12 x 2 = 24cm^2 for 2 triangles
Height of rectangle must be found, so use pythag on triangle
a^2+ b^2 = c^2
16 + 9 =c^2
C=5
A= 5 x 12
= 60
60 x 3 triangles in total is 180cm^2
180cm^2 + 24cm^2 = 204cm^2
Ans: 204cm^2
Answer:
c = 69 and h = 51
Step-by-step explanation:
You will need two different equations here
use variable c as coffee and variable h as hot chocolate
c + h = 120
1.80c + 3.15h = 284.40
By moving variables, you can alter the first equation
h = 120 - c
Now insert this into the second equation
1.80c + 3.15(120 - c) = 284.40
Multiply
1.80c + 378 - 3.15c = 284.40
Subtract the c
-1.35c + 378 = 284.40
Subtract 378 from both sides
-1.35c = -93.6
Divide both sides by -1.35
c = 69
Then plug into the first equation
69 + h = 120
Subtract 69
h = 51
