Answer:
substitution
Step-by-step explanation:
We assume the two equations are ...
You are given an expression for x. Using that in the second equation will result in an immediate solution for y.
... 2(2y+4) -3y = 11 . . . . . substituting 2y+4 for x
.. y +8 = 11
... y = 3
... x = 2·3 +4 = 10
The solution is (x, y) = (10, 3)
<h2>
Answer:</h2>
<u>A direct variation equation is of the form y = m⋅x for some constant value m</u>.
<u>For a direct variation equation passing through</u>
(x,y) = (-11,13)
13 = m × - 11
→ m = - 13/11.
so, as y = m⋅x
y = - 13/11x
<u>Hence, the direct variation equation is [C] - 13/11x</u>.
Answer:
False.
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Geometry</u>
- Radius: <em>r</em>
- Diameter: d = 2r
Step-by-step explanation:
<u>Step 1: Define</u>
Radius = 12 cm
<u>Step 2: Find diameter</u>
- Substitute: d = 2(12 cm)
- Multiply: d = 24 cm
∴ The statement is false and should be 24 cm as the diameter.
Answer:
Independent
Step-by-step explanation:
Dependent Sampling:
Dependent sampling is one in which the individuals in one sample are used to determine the individuals in the other sample.
But the third dash graders are divided into two groups independent of each other.
So the sampling is independent.
It is qualitative because it is showing quality irrespective of the number of students .
Quantitative Sampling is one in which the results change with the number of the individuals / tests etc. But in this experiment the number of the students is fixed so it is showing quality rather than quantity.
