All categories

2 years ago

Helpp please ! need to show work for geometry

Mathematics

1 answer:

podryga [215]2 years ago

3 0

Answer:

45 degrees

Step-by-step explanation:

AOB = 140°

and an the angle bisector(OC) is a line which will divide AOB into 2 equal angles

which is 140÷2= 70

and if AOD = 25 then COD= 70-25

= 45 degrees

hope it helps

You might be interested in

If the difference of two numbers is 43 and the sum of the numbers is 13, what are the numbers?

meriva

Answer:

Numbers are 28 and -15

Step-by-step explanation:

Mark first number X, and second number Y, then:

x-y=43

and

x+y=13

We get system of two equations. Solve it by add both them together:

x-y+x+y=43+13

2x=56

x=28 we get first number

x+y=13

28+y=13

y=13-28

y=-15

4 0

3 years ago

"Match the inequality with its graph below.

Svetllana [295]

The answers for the given inequalities shown in the figures above are the following:
1. x+2y is bigger than or equal to 6 corresponds to the first graph.
2. x-2y>4 corresponds to the third graph.
3. y>3+(1/2)x corresponds to the second graph
4. 4y+2x is smaller than or equal to 16 corresponds to the fourth graph

3 0

2 years ago

ANSWER ASAP PLEASE T~T

ki77a [65]

Answer:

13, 11, 2, 25, 66, 5, 12, 25, 45

Step-by-step explanation:

Right to Left

7 0

2 years ago

Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10

Iteru [2.4K]

Answer:

The number of bacteria $B$ after $d$ days is given by

$B = B_0 (3)^{\frac{1}{10} d}$

where $B_0$ is the initial number of bacteria.

Step-by-step explanation:

The number of bacteria $B$ in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

$B = B_0 *3,$

where $B_0$ is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

$B = (B_0 *3)*3$

after the 3rd day,

$B =( B_0 *3*3)*3$

and so on.

Thus, the formula we get for the number of bacteria after the nth 10-days is

$B = B_0 (3)^n$

where $n$ is is the nth 10-days.

Since, $n$ is 10 days, we have

$d =10n$

$n =\dfrac{1}{10}$

Substituting that into $B = B_0 (3)^n$ , we get:

$\boxed{ B = B_0 (3)^{\frac{1}{10} d}}$

8 0

2 years ago

Children in 50 Households

atroni [7]

Answer:I think it’s 269 because when you do 1,350 divided by 50 it’s 27 then you add 9+2 to get 11/50 then you do 27x11 which gives you 270 and the closest answer to that is 269

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers