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solniwko [45]
3 years ago
12

An arithmetic sequence with a third term of 8 and a constant difference of 5

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad  \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ \hrulefill\\[0.5em] a_3=8\\ n=3\\ d=5 \end{cases} \\\\\\ a_3=a_1+(3-1)5\implies 8=a_1+(2)5 \\\\\\ 8=a_1+10\implies -2=a_1 \\\\\\ \begin{cases} a_1=-2\\ d=5 \end{cases}\implies a_n=-2+(n-1)d

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x>y
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The second step in the process for factoring the trinomial is to:
emmainna [20.7K]
Example:  <span>the second step in the process for factoring the trinomial x^2-3x-40 is to:</span> <span>Well you really should find the sum of the factors of −40 (not 40) </span>
<span>But before you can do that, you need to LIST the factors of −40 (not 40) </span>
<span>−1 * 40 </span>
<span>−2 * 20 </span>
<span>−4 * 10 </span>
<span>−5 * 8 </span>
<span>−8 * 5 </span>
<span>−10 * 4 </span>
<span>−20 * 2 </span>
<span>−40 * 1 </span>

<span>NOW we find the sum of the factors of −40 </span>
<span>−1 + 40 = 39 </span>
<span>−2 + 20 = 18 </span>
<span>−4 + 10 = 6 </span>
<span>−5 + 8 = 3 </span>
<span>−8 + 5 = −3 </span>
<span>−10 + 4 = −6 </span>
<span>−20 + 2 = −18 </span>
<span>−40 + 1 = −39 </span>

<span>Then we choose the factors of −40 whose sum is −3 ---> −8 and 5 </span>
<span>x^2 − 3x − 40 = (x − 8) (x + 5) </span>

<span>So FIRST step is B, SECOND step is C, and final step is factoring. </span>
What Rita did was combine these 2 steps together, which you will learn to do as you get better at factoring.
8 0
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