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larisa86 [58]
3 years ago
7

The probability that a farmer is in debt is 0.700. The probability that a farmer is in debt and also lives in the Midwest is 0.2

80. The probability that a randomly selected farmer lives in the Midwest given that he is in debt is?
Mathematics
1 answer:
bogdanovich [222]3 years ago
5 0

Answer:

0.4

Step-by-step explanation:

Given that:

P(debt) = P(D) = Probability of being in debt = 0.7

P(debt n Midwest) = P(Dn M) = probability of being in debt and lives in Midwest = 0.280

The probability that a randomly selected farmer lives in the Midwest given that he is in debt is?

P(M | D) = p(D n M) / p(D)

P(M | D) = 0.280 / 0.7

P(M | D) = 0.4

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Step-by-step explanation:

Divide 5.8/8

5 0
3 years ago
The proportion of students who own a cell phone on college campuses across the country has increased tremendously over the past
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Complete Question

The complete question is shown on the uploaded image  

Answer:

1 ) The correct option B

2) The correct option is  C

3)  The correct option is  C

4)  The correct option is  C

Step-by-step explanation:

From the question we are told that

   The proportion that own a cell phone  is  p = 0.90

    The  sample  size is  n =  15

Generally the appropriate distribution for X is mathematically  represented as

      X  \ is  \ B( n , p )

So  

       X  \ is  \ B( 15 , 0.90 )

Generally the number students that  own a cell phone in a simple random sample of 15 students is mathematically represented as

              \mu  =  n  *  p

              \mu  =  15 *  0.90

              \mu  =   13.5

Generally the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students is mathematically represented as

                \sigma  =  \sqrt{ n *  p *  q }

Where  q is mathematically evaluated as

          q =  1- p

           q =  1- 0.90

           q =  0.10

            \sigma  =  \sqrt{ 15 *  0.90 *  0.10 }

            \sigma  = 1.16

Generally the probability that all students in a simple random sample of 15 students own a cell phone is mathematically represented as

   P(X =  15) =  \left 15} \atop {}} \right.C_{15} *  p^{15} *  q^{15 - 15}    

     P(X =  15) =  \left 15} \atop {}} \right.C_{15} *  (0.90)^{15} *  (0.10 )^{15 - 15}

From the combination calculator  is      \left 15} \atop {}} \right.C_{15} =  1

     P(X =  15) = 1 *  0.205891 *  1

      P(X =  15) = 0.206

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