Determine The number of solutions 3(x-4)=2x+6

Mathematics

1 answer:

Trava [24]3 years ago

3 0

Answer:

The answer will be listed below.

Step-by-step explanation:

First of all, you want x to by itself, so distribute the three to both x and negative 4 so you'll get 3x-12=2x+6.

Now, subtract 2x from both sides and add 12 to both sides and you'll get an answer of x=19. From that, you are able conclude that this equation has one solution.

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Translate the sentence into an inequality.

Vadim26 [7]

Answer:

9(n + 22) ≤ -15

Step-by-step explanation:

9 times the sum of a number and 22 is at most −15

Let n = number

Times = multiplication

Sum = Addition

9 * n + 22

We must add parenthesis on the end on 22 and before n

We must do this because it says 9 times the sum of a number and 22 which means that 9 is being multiplied by both n and 22

We would have 9(n + 22)

9(n + 22) is at most -15

At most meaning that -15 is the highest number that 9(n + 22) can equal

Because it says at most 9(n + 22) can equal -15 or anything less than -15

So at most can be replaced with ≤

9(n + 22) ≤ -15

4 0

2 years ago

Zarrin [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

Write 3x^2-18x-6 in vertex form

Vedmedyk [2.9K]

The standard form of a quadratic equation is $\displaystyle{ y=ax^2+bx+c$ , while the vertex form is:

$y=a(x-h)^2+k$ , where (h, k) is the vertex of the parabola.

What we want is to write $\displaystyle{ y=3x^2-18x-6$ as $y=a(x-h)^2+k$

First, we note that all the three terms have a factor of 3, so we factorize it and write:

$\displaystyle{ y=3(x^2-6x-2)$ .

Second, we notice that $x^2-6x$ are the terms produced by $(x-3)^2=x^2-6x+9$ , without the 9. So we can write:

$x^2-6x=(x-3)^2-9$ , and substituting in $\displaystyle{ y=3(x^2-6x-2)$ we have:

$\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]$ .

Finally, distributing 3 over the two terms in the brackets we have:

$y=3[x-3]^2-33$ .

Answer: $y=3(x-3)^2-33$