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3 years ago

Determine The number of solutions 3(x-4)=2x+6

Mathematics

1 answer:

Trava [24]3 years ago

3 0

Answer:

The answer will be listed below.

Step-by-step explanation:

First of all, you want x to by itself, so distribute the three to both x and negative 4 so you'll get 3x-12=2x+6.

Now, subtract 2x from both sides and add 12 to both sides and you'll get an answer of x=19. From that, you are able conclude that this equation has one solution.

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Write an expression for the following

ycow [4]

Answers:
A) 14 -P
B) (D+F) ^ 8
C) (5x2) + 5
D) C + 6

Enjoy!

5 0

2 years ago

Read 2 more answers

Quadrilateral ABCD is translated to get quadrilateral A’B’C’D’. Vertex A is at (-5, 2), and vertex A’ is at (2, -2). Quadrilater

Rudik [331]

Answer:

vertex B' is at (1, 1)

Step-by-step explanation:

Let us revise the rules of translation of a point

If the point (x, y) translated horizontally to the right by h units then its image is (x + h, y) ⇒ T (x, y) → (x + h, y)

If the point (x, y) translated horizontally to the left by h units then its image is (x - h, y) ⇒ T (x, y) → (x - h, y)

If the point (x, y) translated vertically up by k units then its image is (x, y + k)→ (x + h, y) ⇒ T (x, y) → (x, y + k)

If the point (x, y) translated vertically down by k units then its image is (x, y - k) ⇒ T (x, y) → (x, y - k)

Let us use the rules to solve our question

∵ Vertex A = (-5, 2)

∵ Vertex A' = (2, -2)

→ The coordinates of the two points changed which means the

quadrilateral is translated horizontally and vertically

∵ The x-coordinate of A = -5

∵ The x-coordinate of A' = 2

→ Which means it moves to the right, so use the first rule above

∴ the rule of translation is T (x, y) → (x + h, y)

∴ x → x + h

∵ x = -5 and x + h = 2

∴ -5 + h = 2

→ Add 5 to both sides

∴ -5 + 5 + h = 2 + 5

∴ h = 7

∴ The quadrilateral is translated 7 units right

∵ The y-coordinate of A = 2

∵ The y-coordinate of A' = -2

→ Which means it moves down, so use the 4th rule above

∴ the rule of translation is T (x, y) → (x, y - k)

∴ y → y - k

∵ y = 2 and y - k = -2

∴ 2 - k = -2

→ Add K to both sides

∴ 2 - k + k = -2 + k

∴ 2 = -2 + k

→ Add 2 to both sides

∴ 2 + 2 = -2 + 2 + k

∴ 4 = k

∴ The quadrilateral is translated 4 units down

→ Let us find B'

∵ T (x, y) → (x + h, y - k) is the rule of translation

∵ B = (-6, 5)

∵ h = 7 and k = 4

∴ B' = (-6 + 7, 5 - 4)

∴ B' = (1, 1)

∴ vertex B' is at (1, 1)

6 0

4 years ago

If the square root of 1 over 2 x - 10 added by 3, which inequality can be used to find the domain of f(x)?

jeyben [28]

From the description, we have the function $f(x)= \sqrt{ \frac{1}{2x-10}+3 }$
Since the square root cannot be a negative number, the only thing need to do to find the domain of the function $f(x)$ is take the expression inside the square rot and set it greater or equal than zero:
$\frac{1}{2x-10}+3 \geq 0$
$\frac{6x-29}{2x-10} \geq 0$
$\frac{6x-29}{2(x-5)} \geq 0$
$x \leq \frac{29}{6}$ or $x\ \textgreater \ 5$

We can conclude that we can use the inequality $\frac{1}{2x-10}+3 \geq 0$ to find the domain of $f(x)$ . Also, the domain of $f(x)$ is (∞, $\frac{29}{6}$ ]U(5,∞).

4 0

4 years ago

What is the quadratic. Formula?

balu736 [363]

Answer:

$x = \frac{ - b ± \sqrt{ {b }^{2} - 4ac } }{2a}$