(7x10)+(4×1)+(9×1\100)+(2×1\100)=74.11
Out of the 52 cards in a deck, there are 13 clubs and 4 aces. The given situation is an inclusive event because out of the 4 aces there is one of them that is a club. The probability therefore,
P(ace) + P(club) - P(inclusive event)
Substituting gives,
4/52 + 13/52 - 1/52 = 4/13
The answer is letter C. 4/13.
Answer:
x = -53/8
Step-by-step explanation:
6(2x + 7) = 5x - 11 - x
12x + 42 = 5x -11 - x (Distributive property)
12x + 42 = 4x - 11 (Subtraction property)
8x + 42 = -11 (Subtraction Property)
8x = -53 (Subtraction Property)
<u><em>x = -53/8</em></u>
I would think that it would be the 3:8 one because if you do the math, 8-3 is 5 and 12-5 is 7. The only reason Im doing it this way is because its the only way I can set it up.
so you have more of a difference with the 12:5 one and less of a difference with the 3:8.
I hope I helped a bit
Answer:
0.205 ; 0.117 ; 0.999
Step-by-step explanation:
Using binomial probability distribution :
P(x =x) = nCx * p^x * (1 - p)^(n - x)
Probability of success, p = 0.5
P(x = 4) = 10C4 * 0.5^4 * 0.5^6
P(X = 4) = 0.205078125
B.) 3 heads and 7 tails
P(X = 7) = 10C7 * 0.5^7 * 0.5^3
P(X = 7) = 120 * 0.0009765625
P(X = 7) = 0.117
P(atleast one head)
P(x greater than equal to 1) = p(x =1) +... P(x = 10)
Using a binomial probability calculator :
P(x greater than equal to 1) = 0.999
