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3 years ago

Sylvie finds the solution to the system of equations by graphing.

Mathematics

1 answer:

Taya2010 [7]3 years ago

4 0

Answer:

The solution is at (-0.5,0.5).

Step-by-step explanation:

I graphed both equations on the graph below to show you where the solution of the system is.

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Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AD = 4

Vinil7 [7]

Answer:

BD = 6

Step-by-step explanation:

Theorem: The altitude to the hypotenuse of a right triangle is the mean proportional between the segments of the hypotenuse.

So, $\frac{4}{BD} = \frac{BD}{9}$

$BD^{2} = 36$

BD = 6

See how easy that is IF you know the theorem.

4 0

2 years ago

A^8-12a^4+36 in factored form

ira [324]

Answer:

a^8 - 12a^4 + 36

= (a^4)^2 - 2*a^4*6 + 6^2

= (a^4 - 6)^2

3 0

3 years ago

Suppose sin a = 12/13 and sin b= 5/11. FInd cos(a+b)

m_a_m_a [10]

Answer:

1.28 or 912/715

Step-by-step explanation:

sine= opposite side/hypotenuse

cos=adjacent/ hypotenuse

sine a= 12/13 using the Pythagorean Theorem and solve for the missing side. (which is the adjacent side)

cos a = 5/13

Do the same for sine b

cos b= 9.8/11

add both the cosine value

(5/13)+(9.8/11)=1.28 or 912/715 in fraction form

6 0

2 years ago

If VT=2,what is the length of PT?

marusya05 [52]

Step-by-step explanation:

$\underline{ \underline{ \text{Given : }}}$

Perpendicular ( P ) = VT = 2
Base ( b ) = PT
$\theta = \tt{60 \degree}$

$\underline{ \underline{ \text{Solution}}} :$

$\tt{ \tan(60 \degree) = \frac{perpendicualar}{base}}$

⟶ $\tt{ \sqrt{3} = \frac{2}{PT}}$

⟶ $\tt{ \sqrt{3} \: PT= 2}$

⟶ $\tt{PT = \frac{2}{ \sqrt{3}} }$

⟶ $\tt{PT= \boxed{\tt{ \frac{2 \sqrt{3} }{{3} }}}}$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0

3 years ago

Use the functions f(x) = 4x² + 3 and g(x) = 3x + 2 to evaluate the following.

natita [175]

Answer:

Step-by-step explanation:

f(-2)= 4(-2)^2 + 3 = 4(4) + 3 = 16 + 3 = 19

g(19) = 3(19) + 2 = 57 + 2 = 59

g(-2)= 3(-2) + 2 = -6 + 2 = -4

f(-4)= 4(-4)^2 + 3 = 64 + 3 = 67

7 0

2 years ago

Read 2 more answers