Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
6, 10, 8
Step-by-step explanation:
aₙ= aₙ₋₁ - (aₙ₋₂ - 4)= aₙ₋₁ - aₙ₋₂ + 4
a₅= -2
a₆= 0
-----------
aₙ₋₂= aₙ₋₁ - aₙ + 4
- a₄= a₅- a₆ + 4 = -2 - 0 + 4 = 2
- a₃= a₄ - a₅ + 4 = 2 - (-2) + 4 = 8
- a₂= a₃ - a₄ + 4 = 8 - 2 + 4 = 10
- a₁= a₂ - a₃ + 4 = 10 - 8 + 4 = 6
The first 3 terms: 6, 10 and 8
Answer: Its a cone
Explanation:
When a right angle triangle is rotated about any of its leg a cone is formed.
Answer:
a. x = 14
b. Perimeter = 77
Step-by-step explanation:
a. Based on the Triangle Proportionality Theorem:



Cross multiply


Add 2 to both sides


Divide both sides by 2
x = 14
b. Perimeter of ∆QRS = RQ + QS + RS = (2x - 2) + 13 + 17 + (21 - 7) + 7
Plug in the value of x
= (2(14) - 2) + 13 + 17 + 14 + 7
= 26 + 13 + 17 + 14 + 7
= 77
900/18=50
On average, 50 students rode each bus
Hope this helps!