All categories

3 years ago

WILL GIVE BRAINLIEST! In any boxplot, what percent of the data is above the 3rd quartile?

1 answer:

5 0

75% because a third quartile is 3/4 which is 75% which if you break each fourth down it would be 25% so then you multiply 25%x3 to get 75%

You might be interested in

Solve <br> -15-2g+6g=1+6g

katrin [286]

<span>-15-2g+6g=1+6g
Combine like terms
-2g=16
Divide by -2 on both sides
g=-8</span>

7 0

3 years ago

Read 2 more answers

7. The ratio of wins to losses for Loyola basketball was 4 to 1. If the team played 30 games, how

RoseWind [281]

Answer:

24:6

Step-by-step explanation:

It is 4 to 1. The ratios added up is 5. So 30 divided by 5 is 6. So 1 (the ratio) is 6 games. 4x6=24. So the new ratio is 24 to 6. 24 wins and 6 losses.

4 0

3 years ago

An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a

MAVERICK [17]

Answer:

Probability Mass Function:

x: 0 1 2 3

P(x): 0.000064 0.004608 0.115902 0.884736

Step-by-step explanation:

We are given the following information:

We treat correct classification as a success.

P(correct classification) = 0.96

Then the number of classification follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3 and x = 0, 1, 2, 3

We have to evaluate:

$P(x = 0)\\= \binom{3}{0}(0.96)^0(1-0.96)^3\\=0.000064$

$P(x = 1)\\= \binom{3}{1}(0.96)^1(1-0.96)^2\\=0.004608$

$P(x = 2)\\= \binom{3}{2}(0.96)^2(1-0.96)^1\\=0.115902$

$P(x = 3)\\= \binom{3}{3}(0.96)^3(1-0.96)^0\\=0.884736$

PMF:

x: 0 1 2 3

P(x): 0.000064 0.004608 0.115902 0.884736

8 0

3 years ago

PLEASE HELP QUESTION 10 ASAP!!!!! THANK YOU!!!!

vovikov84 [41]

Answer:

Every 34 days, te amount of food decreases by 3 cups.

7 0

3 years ago

Read 2 more answers

G(1)=-5<br> g(2)=3<br> g(n)=g(n-2)+g(n-1)<br> g(3)=?

olga_2 [115]

Answer:

Step-by-step explanation:

$g(1)=-5\\g(2)=3\\g(n)=g(n-2)+g(n-1)\\\\g(3)=?\\\\\text{Put}\ n=3\ \text{to the formula of}\ g(n):\\\\g(3)=g(3-2)+g(3-1)=g(1)+g(2)\\\\\text{Substitute given value of}\ g(1)\ \text{and}\ g(2):\\\\g(3)=-5+3=-2$

4 0

3 years ago