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Dmitry [639]
1 year ago
15

Help me with this problem please

Mathematics
2 answers:
Alexxx [7]1 year ago
5 0
Inferential Statistics!
Flauer [41]1 year ago
4 0
Inferential statistics
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Hlp me with this math problem
zaharov [31]

Answer:

0.5l+0.2s

Step-by-step explanation:

0.10x5<em>l</em> equals 0.5<em>l</em>

0.10x2<em>s</em> equals 0.2<em>s</em>

7 0
2 years ago
the point 3,2 lies on a circle.what is the exact length of the radius of this circle if the center is located at (-1,-4)
Crazy boy [7]
You can use the distance formula to solve this.

Distance Formula:
d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}

I am going to use point (3,2) as point 1 and (-1,-4) as point 2
Insert the points into the formula
d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}
d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}
Solve:
d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}
d = \sqrt{(-4)^2 + (-6)^2}
d = \sqrt{16 + 36}
d = \sqrt{52}
d = \sqrt{52} = \sqrt{4}\sqrt{13}
d = \sqrt{52} = 2 \sqrt{13}
d = 2 \sqrt{13}
radius = 2 \sqrt{13} = 7.2111


5 0
3 years ago
PLEASE HELP ASAP 35 POINTS
podryga [215]

Your answer is A

It cannot be C because the line y > -2  uses the (>) greater than symbol.

When equations have a greater than symbol, they are graphed using a <u>dotted line. </u>

It cannot be D because the line is  y ≤ - l x-1 l

with the less than or equal to sign (≤) , you use a <u>solid line</u> to graph


With the<u> greater than</u> symbol for y > -2 , the shaded region must be <em>above </em>this line.

With the <em>less than </em>or equal to sign in y ≤ - l x-1 l , the shaded region must be <em>below </em>the line.


Hope I helped - message me if you have any questions :)

5 0
3 years ago
For #3 how do you find the radian measure? Is there a formula?
Novosadov [1.4K]
Yea, there's a formula :
radians = degrees × π / 180°
6 0
3 years ago
Complete the square than convert to vertex form. y=2x^2+8x-9​
8_murik_8 [283]

y=2x^2+8x-9\\D=b^2-4ac\\D=64-4(2)(-9)\\D=64+72 > 0

There are 2 roots so the only way to complete the square is,

y=2x^2+8x-9\\y=2[(x^2+4x)]-9\\y=2[(x^2+4x+4)-4]-9\\y=2[(x+2)^2-4]-9\\y=2(x+2)^2-8-9\\y=2(x+2)^2-17

Just factor 2 out of 2x^2+8x (just ignore the -9) then find the number that will make the terms be able to complete the square.

then complete the square and multiply 2 inside the brackets.

subtraction as you already get the vertex form and know how to complete the square.

Vertex Form: y=2(x+2)^2-17

3 0
3 years ago
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