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Phoenix [80]
3 years ago
7

In a regular polygon each interior angle is 140° greater than each exterior angle. Calculate the number of sides of the polygon​

Mathematics
1 answer:
pochemuha3 years ago
6 0

Answer:

18 sides.

Step-by-step explanation:

The interior and exterior angles sum to 180 so:

       I + E = 180

also  I - E = 140       (given)

So, adding to eliminate E:

      2I = 320

I = 160 degrees and the external angle E = 1809 - 160 = 20 degrees.

Since the sum of all exterior angles in a polygon = 360 degrees

- the number of sides = 360 / 20 = 18.

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Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

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This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

Then

\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356

t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14

t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

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