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ss7ja [257]
3 years ago
11

If a+ b + c= -6 and x +y = 5, what is 9y +9x - 10a-10c -10b ?

Mathematics
2 answers:
Lisa [10]3 years ago
5 0

Answer:

9y +9x - 10a-10c -10b = 105

Step-by-step explanation:

Given

a+b+c = -6 and x+y = 5

We have to find 9y +9x - 10a-10c -10b

Rearranging the terms

9x+9y-10a-10b-10c

Simplifying will give us:

= 9 (x+y) - 10(a+b+c)

Putting the values of x+y and a+b+c

= 9(5) -10(-6)

=45+60

=105

Therefore,

9y +9x - 10a-10c -10b = 105 ..

Gre4nikov [31]3 years ago
3 0

Answer:

9y + 9x - 10a - 10c - 10b  = 105

Step-by-step explanation:

It is given that,  a+ b + c = - 6 and x + y = 5

<u>To find the value of given expression</u>

Let the expression be 9y +9x - 10a-10c -10b

9y +9x - 10a -10c -10b  = 9(y + x) - 10(a + c + b )

 = 9(x + y) - 10(a + b + c)

 = 9 * (5) - 10 * (-6)

 = 45 + 60

 = 105

Therefore 9y + 9x - 10a - 10c - 10b  = 105

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What is the median of the following numbers: 120, 35, 42, 119, 120.5, 99, 72 ? *
Roman55 [17]

Answer:

the median is 99

Step-by-step explanation:

(lowest) 35, 42, 72, <u>99</u>, 119, 120, 120.5 (highest)

the median is the middle #

the middle # is 99

6 0
3 years ago
Write 2 decimals whose product is 0.16
Nitella [24]
0.4 and 0.4 or 0.8 and 0.2 

Hope this helps :)
8 0
3 years ago
Read 2 more answers
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
Help!!!!
shusha [124]

Answer:

x = 4

Step-by-step explanation:

Since JB is the bisector of AD and the length of AD is given as 24 we can conclude that AZ is 12 (half of AD)

2x + 4 = 12

2x = 8

x = 4

3 0
4 years ago
Can someone help me with this problem
user100 [1]

Answer:

About 110.6

Step-by-step explanation:

The sine of an angle is the length of the opposite side divided by the length of the hypotenuse.

\sin 19= \dfrac{36}{x} \\\\x=\dfrac{36}{\sin 19}\approx 110.6

Hope this helps!

5 0
3 years ago
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