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3 years ago

If a+ b + c= -6 and x +y = 5, what is 9y +9x - 10a-10c -10b ?

Mathematics

2 answers:

Lisa [10]3 years ago

5 0

Answer:

9y +9x - 10a-10c -10b = 105

Step-by-step explanation:

Given

a+b+c = -6 and x+y = 5

We have to find 9y +9x - 10a-10c -10b

Rearranging the terms

9x+9y-10a-10b-10c

Simplifying will give us:

= 9 (x+y) - 10(a+b+c)

Putting the values of x+y and a+b+c

= 9(5) -10(-6)

=45+60

=105

Therefore,

9y +9x - 10a-10c -10b = 105 ..

Gre4nikov [31]3 years ago

3 0

Answer:

9y + 9x - 10a - 10c - 10b = 105

Step-by-step explanation:

It is given that, a+ b + c = - 6 and x + y = 5

To find the value of given expression

Let the expression be 9y +9x - 10a-10c -10b

9y +9x - 10a -10c -10b = 9(y + x) - 10(a + c + b )

= 9(x + y) - 10(a + b + c)

= 9 * (5) - 10 * (-6)

= 45 + 60

= 105

Therefore 9y + 9x - 10a - 10c - 10b = 105

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Please find the attachment.

We have been given that secants AC and DB intersect at point E inside the circle. Given that the measure of arc $CD = 40^o$ , arc $AB = 60^o$ , and arc $BC = 160^o$ . We are asked to find the measure of angle AED.

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