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cluponka [151]
4 years ago
6

What is period given by y=-2sin(2pi/7x)

Mathematics
1 answer:
yaroslaw [1]4 years ago
7 0
Whenever the things contained by the sin function = a factor of 2pi , a complete cycle is made.
so in this case, whenever 2pi/7x = 2pi , a complete cycle is made.
2pi/7x = 2pi
1/7x = 2pi/2pi
1/7x = 1
7x = 1
x = 1/7
therefore, the period is x = 1/7 for every cycle
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4 years ago
Write an equation of the line that passes through a pair of points:<br> (-5, - 2), (4, 5)
attashe74 [19]

Answer (<u>assuming it can be written in slope-intercept form)</u>:

y = \frac{7}{9} x+\frac{17}{9}

Step-by-step explanation:

1) First, find the slope of the line. Use the slope formula, m = \frac{y_2-y_1}{x_2-x_1}. Substitute the x and y values of the given points into the formula and solve:

m = \frac{(5)-(-2)}{(4)-(-5)} \\m  = \frac{5+2}{4+5} \\m = \frac{7}{9}

So, the slope is \frac{7}{9}.

2) Now, use the point-slope formula y-y_1 = m (x-x_1) to write the equation of the line. Substitute m, x_1, and y_1 for real values.

Since m represents the slope, substitute \frac{7}{9} for it. Since x_1 and y_1 represent the x and y values of one point the line intersects, choose from any one of the given points (it doesn't matter which one, either way the result equals the same thing) and substitute its x and y values into the formula as well. (I chose (4,5), as seen below.) From there, isolate y to place the equation in slope-intercept form (y = mx + b format) and find the following answer:

y-(5) = \frac{7}{9} (x-(4))\\y-5 = \frac{7}{9} (x-4)\\y -5=\frac{7}{9} x-\frac{28}{9}\\y = \frac{7}{9}  x-\frac{28}{9} +\frac{45}{9}\\y = \frac{7}{9} x+\frac{17}{9}

6 0
3 years ago
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