What is the solution set of these system5x-2y=17 and 4x-7=13?
1 answer:
Answer:
x=5
y=4
Step-by-step explanation:
Step 1:
Let us solve for <em>x</em> using the equation by <u>isolating terms containing the variable</u>:
Great! <em>x</em> is 5... let's find <em>y</em>.
Step 2:
Since we know the value of <em>x</em>, we can use what we know to find <em>y</em> using the <u>other equation</u>:
<em>Given that x=5, we can </em><u><em>replace</em></u><em> x with 5</em>.
<em>I hope this helps! Let me know if you have any questions :)</em>
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Answer:
Step-by-step explanation:
The goal to solving any equation is to have x = {something}. That means we need to get the x out from underneath that radical. It's a square root, so we can "undo" it by squaring. Square both sides because this is an equation. Squaring both sides gives you
Get everything on one side of the equals sign and set the quadratic equal to 0:
Throw this into the quadratic formula to get that the solutions are x = 5 and -8. We need to see if only one works, both work, or neither work in the original equation.
Does ?
and
and 5 = 5. So 5 works. Let's try -8 now:
and
so
-8 = 8? No it doesn't. So only 5 works. Your choice is the third one down.