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vovangra [49]
3 years ago
13

Mr.Carter owned a ranch with 7 1/4 acres. Last year ,he bought 3 1/5 acres of land from his neighbor. Then he sold 2 1/4 acres.

How many acres does Mr.Carter own now?
A) 10 9/20 acres
B) 8 1/5 acres
C) 12 7/10 acres
D) 6 3/10 acres
Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Answer:

B - 8 1/5 acres

Step-by-step explanation:

1. Subtract 7 1/4 - 2 1/14 (what he sold) = 5 acres

2. Add 5 + 3 1/5 (what he bought)  = 8 1/5 acres

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What percentage of 3 is 4?
Artyom0805 [142]

Answer:

13.333% of 3 is 4.

Step-by-step explanation:

Take missing value = x

x% of 3 = 4

x/100 × 3 = 4

3x/100 = 4

3x = 400

x = 400/3

x = 13.333

Hope it helps ⚜

5 0
2 years ago
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Basile [38]

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The rational values are :

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and

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The Irrational values are :

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6 0
3 years ago
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What is the x please answer me quick ​
nordsb [41]
First u do a squared +b squared =c squared aka pythagorean theorem then so u already have c squared so you would do 5x5=25 and 13x13=169 so then the equation would be 25+?=169 then do 169-25 which equals 144 and then do the square root of that which is 12 THE ANSWER IS 12
4 0
3 years ago
Which statement is NOT true? A. All isosceles triangles are also equilateral triangles. B. All equilateral triangles are also is
Alecsey [184]
Hello there!

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Hope this helps and have a great day! :)
5 0
4 years ago
Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

8 0
1 year ago
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