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Delvig [45]
3 years ago
7

Steve has a hammer that is 0.29 meters long. Which expression is equal to the length, in meters, of Steve's hammer?

Mathematics
1 answer:
Damm [24]3 years ago
7 0

Answer:

x = 0.29 m

Step-by-step explanation:

Given :

The length of the hammer is = 0.29 m

The hammer is a tool that may be used in various operation or work by mechanics, plumbers, or masonries and even by normal people.

So let the length of the hammer be x.

The length of the hammer is expressed in meters or inches or centimeters.

Therefore, the expression of length of the hammer is expressed as x = 0.29 m.

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3 years ago
Using the graphing function on your calculator, what is the solution to the system of equations show below?
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Answer:

ima redo my answer but

Step-by-step explanation:

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4 0
3 years ago
What is 2x-(x-2)=-2-(x-1)​
bezimeni [28]
Distribute first so
2x-x+2=2-x+1
Combine like terms so
x+2=3-x
Get terms on the same side so
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8 0
4 years ago
Bobby is testing the effectiveness of a new cough medication. There are 100 people with a cough in the study. Seventy patients r
Tresset [83]

Answer:

0.665

Step-by-step explanation:

Given:  100 people are split into two groups 70 and 30.  I group is given cough syrup treatment but second group did not.

Prob for a person to be in the cough medication group = 0.70

Out of people who received medication, 34% did not have cough

Prob for a person to be in cough medication and did not have cough

=\frac{0.70(34)}{60}=0.397


Prob for a person to be not in cough medication and did not have cough

=\frac{0.3(20)}{30}=0.20

Probability for a person not to have cough

= P(M1C')+P(M2C')

where M1 = event of having medication and M2 = not having medication and C' not having cough

This is because M1 and M2 are mutually exclusive and exhaustive

SO P(C') = 0.397+0.2=0.597

Hence required prob =P(M1/C') = \frac{0.397}{0.597}=0.665

4 0
3 years ago
Read 2 more answers
1/3(m-1)=-5<br> Please help
dezoksy [38]

Answer:

m=-14 I hope this helps u

Step-by-step explanation:


6 0
4 years ago
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