9514 1404 393
Answer:
x = 16
Step-by-step explanation:
Corresponding sides are proportional.
BE/CD = AE/AD
20/(3x+8) = (x-1)/(x-1+27)
20(x+26) = (3x+8)(x -1)
In standard form, this is ...
3x^2 -15x -528 = 0
x^2 -5x -176 = 0 . . . . . . divide by 3
(x -16)(x +11) = 0 . . . . . . . factor
x = 16
__
This is the positive value that makes the product zero. x=-11 will also make the product 0, but gives negative segment lengths in the geometry. It is an extraneous solution.
$7.22 would be the answer because 70% of 10.31 is what you are looking for which is 7.217 which is rounded to 7.22 I know this is right because I just learned this and I am in advanced math 6th grade.
Answer:
1) C) sin(θ) = 119/169
2) D) cos(θ) = 120/169
Step-by-step explanation:
The mnemonic SOH CAH TOA expresses the relationships you need for answering these questions.
Sin(θ) = Opposite/Hypotenuse = 119/169 . . . . . problem 1
Cos(θ) = Adjacent/Hypotenuse = 120/169 . . . . problem 2
There are two <em>true</em> statements:
- When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
- V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.
<h3>How to use composition between two function</h3>
Let be <em>f</em> and <em>g</em> two functions, there is a composition of <em>f</em> with respect to <em>g</em> when the domain of <em>f</em> is equal to the range of <em>g</em>. In this question, the <em>domain</em> variable of the function V(r) is replaced by substitution.
If we know that V(r) = (4/3) · π · r³ and r(t) = (1/4) · t², then the composite function is:
V(t) = (4/3) · π · [(1/4) · t²]³
V(t) = (4/3) · π · (1/64) · t⁶
V(t) = (1/48) · π · t⁶
There are two <em>true</em> statements:
- When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
- V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.
To learn on composition between functions: brainly.com/question/12007574
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