X= # gallons of pure water that should be evaporated
The total amount of salt must be equal before and after evaporation.
STEP 1
BEFORE EVAPORATION: multiply the percent of salt in the solution before evaporation by the total gallons of solution
= 12% * 160 gallonsconvert 12% to decimal form (12% ÷ 100)
= 0.12 * 60
STEP 2
AFTER EVAPORATION: subtract the number of gallons of pure water that should be evaporated from the total number of gallons of the solution and multiply by the percent of salt in the solution after evaporation
= 20% * (160 - x)convert 20% to decimal form (20% ÷ 100)
= 0.20(160 - x)
STEP 3
Set the before & after evaporation equations equal to one another to solve for x.
0.12 * 160= 0.20(160 - x)multiply 0.20 by each term in parentheses
19.2= (0.20 * 160) + (0.20 * -x)multiply in parentheses
19.2 = 32 - 0.20xsubtract 32 from both sides
-12.8= -0.20xdivide both sides by -0.20
64 gallons= x
CHECK:substitute x= 64 into the step 3 equation
0.12 * 160= 0.20(160 - x)19.2= 0.20(160 - 64)subtract in parentheses19.2= 0.20(96)19.2= 19.2
ANSWER: 64 gallons of pure water should be evaporated.
Hope this helps! :)
The answer to that question is 48. All you do is muliply 4*1.5*8=48
Answer:
would be glad to help but im not suree
Step-by-step explanation:
The answer you picked is correct.
Answer and explanation:
There are six main trigonometric ratios, namely: sine, cosine, tangent, cosecant, secant, cotangent.
Those ratios relate two sides of a right triangle and one angle.
Assume the following features and measures of a right triangle ABC
- right angle: B, measure β
- hypotenuse (opposite to angle B): length b
- angle C: measure γ
- vertical leg (opposite to angle C): length c
- horizontal leg (opposite to angle A): length a
- angle A: measure α
Then, the trigonometric ratios are:
- sine (α) = opposite leg / hypotenuse = a / b
- cosine (α) = adjacent leg / hypotenuse = c / b
- tangent (α) = opposite leg / adjacent leg = a / c
- cosecant (α) = 1 / sine (α) = b / a
- secant (α) = 1 / cosine (α) = b / c
- cotangent (α) = 1 / tangent (α) = c / b
Then, if you know one angle (other than the right one) of a right triangle, and any of the sides you can determine any of the other sides.
For instance, assume an angle to be 30º, and the lenght of the hypotenuse to measure 5 units.
- sine (30º) = opposite leg / 5 ⇒ opposite leg = 5 × sine (30º) = 2.5
- cosine (30º) = adjacent leg / 5 ⇒ adjacent leg = 5 × cosine (30º) = 4.3
Thus, you have solved for the two unknown sides of the triangle. The three sides are 2.5, 4.3, and 5.