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3 years ago

Can somebody help me with thiss??

Mathematics

1 answer:

Strike441 [17]3 years ago

8 0

I guess it’s options (d)

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Elena and Noah are each filling a bucket with water. Noah's bucket is 2/5 full and the water weighs 2 1/2 pounds. How much does

Xelga [282]

Answer:

6.25 pounds

Step-by-step explanation:

The number of pounds of water the bucket holds is ...

pounds/bucket = (2.5 pounds)/(0.4 bucket) = 6.25 pounds/bucket

8 0

3 years ago

Read 2 more answers

A 1L solution containing 25,000 units of heparin must run at 30mL/hr. How much heparin is administered per hour?

slamgirl [31]

Answer:

750 units

Step-by-step explanation:

As given in question,

speed of solution = 30 mL/hr

1 L of solution contains heparin = 25000 units

=> 1000 mL of solution contains heparin = 25000 units

$=>\ \textrm{1 mL of solution contains heparin}\ =\ \dfrac{25000}{1000}\ units$

= 25 units

Hence, 30 mL of solutions contains heparin = 30 x 1 mL of solution contains heparin

= 30 x 25

= 750 units

Hence, heparin administered per hour = 750 units

7 0

3 years ago

Jamie and Ryan work at the grocery store. The wages earned for the weekend are shown in the table and graph. Who gets paid more

MissTica

Without the graph to look at, there is no way to answer that question. Good luck to you.

8 0

3 years ago

The container that holds the water for the football team is 1/5 full. After pouring in 14 gallons of water, it is 7/10 full. How

natulia [17]

X= 23 1/3 or 23.333... or 23 3/9 $1/5x+14=7/10x$

8 0

3 years ago

Part 1: Simplify each expression.<br> Use the trigonometric identities to simplify each expression.

stepladder [879]

Answer:

$\cos ^2\left(x\right)$

Step-by-step explanation:

You will need to apply some basic trig identities here:

$\sec ^2\left(\frac{\pi }{2}-x\right) \\\\=> \frac{1}{\cos ^2\left(\frac{\pi }{2}-x\right)}\\\\=> \frac{1}{\sin ^2\left(x\right)}$

Now we substitute this value back into the given equation:

$\left(\frac{1}{\sin \left(x\right)}\right)^2\left(\sin ^2\left(x\right)-\sin ^4\left(x\right)\right)\\\\=> \frac{1\cdot \left(\sin ^2\left(x\right)-\sin ^4\left(x\right)\right)}{\sin ^2\left(x\right)}\\\\=> \frac{\sin ^2\left(x\right)-\sin ^4\left(x\right)}{\sin ^2\left(x\right)}\\\\=> \frac{\sin ^2\left(x\right)\left(1-\sin ^2\left(x\right)\right)}{\sin ^2\left(x\right)}\\\\=> 1-\sin ^2\left(x\right)\\\\=> \cos ^2\left(x\right)$

Hope that helps!

4 0

3 years ago