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3 years ago

I need help with this math question pleaseeeee!!

Mathematics

1 answer:

adell [148]3 years ago

4 0

The answer I think it is (3,1)

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Find the percent of decrease from 270 to 200. Round to the nearest 10th of a percent if necessary.

choli [55]

270-200 = 70

70/200 = 0.35 = 3.5%

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3 years ago

What is greater 11% or 3/25?

Tema [17]

Answer:

3/25 is greater.

Step-by-step explanation:

As a percent, 3/25 would be 12% which is greater than 11%.

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4 years ago

Find the indicated missing side length using trig. Round your answer to the nearest tenth.

alisha [4.7K]

We have $\sin 58^\circ=\frac{14}{x},$ so $x=\frac{14}{\sin 58^\circ}\approx\boxed{16.5}.$

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3 years ago

What is 1/4(x+16)-x equal too

schepotkina [342]

1/4(x + 16) - x =

First, distribute the 1/4.

= 1/4x + 1/4 * 16 - x

= 1/4x + 4 - x

= 1/4x + 4 - 4/4x

= 1/4x - 4/4x + 4

= -3/4x + 4

$= -\dfrac{3}{4}x + 4$

8 0

3 years ago

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

4 0

3 years ago