1) When finding a median, order your numerical list from smallest to larger, as so: 2,2,3,4,5,6,8,9.
2) Then start eliminating numbers from each side of the order; (The bolded numbers will be removed.)
2,2,3,4,5,6,8,9
2,3,4,5,6,8,9
2,3,4,5,6,8
3,4,5,6,8
3,4,5,6
4,5,6
4,5
3) Since there is an even number of digits in your list, you will have to add the last two digits and then divide them by two. 4 and 5 are the last numbers standing, (4+5=9)(9/2=4.5) and therefore your answer, would be 4.5, or B.
0.7 can be turned into a fraction which can be 70/100 and 3/4 can be turned into 75/100 so 3/4 would be greater
Solution:
Given that the point P lies 1/3 along the segment RS as shown below:
To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have
Using the section formula expressed as
![[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2C%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5D)
In this case,
where
Thus, by substitution, we have
![\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5B%5Cfrac%7B1%282%29%2B2%28-7%29%7D%7B1%2B2%7D%2C%5Cfrac%7B1%284%29%2B2%28-2%29%7D%7B1%2B2%7D%5D%20%5C%5C%20%5CRightarrow%5B%5Cfrac%7B2-14%7D%7B3%7D%2C%5Cfrac%7B4-4%7D%7B3%7D%5D%20%5C%5C%20%3D%5B-4%2C%5Ctext%7B%200%5Crbrack%7D%20%5Cend%7Bgathered%7D)
Hence, the y-coordinate of the point P is
Answer:
7 Quarters and 3 dimes
Step-by-step explanation:
You have to find how many quarters (0.25) and dimes (0.10) are in $2.05. There are 7 quarters, which will add up to $1.75. You can't have 8 quarters because then you would have 2 dollars, and there wouldn't be enough for a dime, there would only by 5 cents left, or a nickle. Then, you find out how many nickels you need, which is 3.
.10x3=.30. 1.75+0.3=2.05.
I hope you understood:)
First distribute in the 2 on the left side to get 6d+6=7+6d
Then, you would combine the variables to be on one side of the equation by doing -6d. However, this would cancel out the d by leaving you with 0d+6=7. That is the same thing as saying 6=7.
The answer to this equation is no solution because 6 is NOT equal to 7.
